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inessss [21]
2 years ago
6

What is the difference in the costs for a one-night stay with and without breakfast?

Mathematics
1 answer:
ad-work [718]2 years ago
6 0

Answer:

$23.12

Step-by-step explanation:

With breakfast included the total would be $142.99. Without breakfast it would be $119.87. So to get the difference it would be:

$142.99 - $119.87 = <em>$23.12</em>

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One third of a number Y
vampirchik [111]

Answer:

⅓y

Step-by-step explanation:

\frac{1}{3}  \times y \\  =  \frac{1}{3} y

4 0
4 years ago
Please help with this question
goldfiish [28.3K]
Second answer box, try that
3 0
3 years ago
Please help ASAP really need this
Aleonysh [2.5K]

Answer:

21.79 + c \leq 25

Joshua can spend up to 3.21 on a card.

Step-by-step explanation:

21.79 + c \leq 25 is the correct equation because Joshua is spending 21.79 on flowers, a certain amount on the card, and the maximum he can spend is 25. That is why you use the less than or equal to sign.

To solve, first subtract 21.79 from both sides to get: c \leq 3.21. This means that Joshua can spend up to 3.21 on a card.

Hope it helps!

3 0
3 years ago
Write 0.76 as a fraction.
marshall27 [118]

Answer:

76/99

Step-by-step explanation:

76 ÷ 99 = 0.767676....

6 0
3 years ago
Read 2 more answers
Evaluate log 2 base 8​
iren2701 [21]

Answer:  The correct answer is:  " 3 " .

_______________________________

Step-by-step explanation:

_______________________________

The problem given is:

_______________________________

Evaluate:  log 2 base 8 .

_______________________________

Rewrite as:  " log_2}8 = ? _______________  " ;  log_2}8 = ? _______________

_______________________

Take note of the following definition of a logarithm:

_______________________

"   log_{m}n = a " ;  ↔  " m^{a} =n  "  ;

_______________________

in which:  m  refers to the "base" ;

               n  refers to the "argument" ;

               a  refers to the "exponent" ;

______________________________

As such:

       " log_2}8 = ? _______________ "

      ⇔ " 2^{x} = 8 " ; Solve for "x" ;  

 _______________

 Note:  

  2⁰ = 1 ;

  2¹ = 2 ;

  2² = 2 * 2 = 4 ;

  2³ = 2 * 2 * 2 = 8 .

___________________

 → " 2^{x} = 8 " ;

 → " 2^{3} = 8 " ;  since: " 2^{3} = 2  *2 *2 = 8 " ;

 → as such:   " x = 3  " ;

______________________

Thus:

"log 2 base 8 " ;

          = log{_{2}}8 = 3  .

_______________________

Hope this helps!

Best wishes to you!

3 0
3 years ago
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