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olasank [31]
2 years ago
13

Please help pethagriem entherum

Mathematics
2 answers:
igor_vitrenko [27]2 years ago
4 0

Answer :

  • 13

\:

Step-by-step explanation :

Here, A right angled triangle is given with the measure of two sides and we are to find the measure of the third side.

We'll find the measure of third side with the help of the Pythagorean theorem,

\\ {\longrightarrow \pmb{\sf {\qquad (Hypotenuse {)}^{2}= (Base) {}^{2} + (Perpendicular {)}^{2} }}} \\ \\

Here,

  • The Base is 12

  • The Perpendicular is 5

  • The Hypotenuse is c.

\:

So, substituting the values in the formula we get :

\\ {\longrightarrow \pmb{\sf {\qquad (c {)}^{2}= (12) {}^{2} + (5 {)}^{2} }}} \\

{\longrightarrow \pmb{\sf {\qquad (c {)}^{2}= 144 + 25 }}} \\

{\longrightarrow \pmb{\sf {\qquad (c {)}^{2}= 169 }}} \\

{\longrightarrow \pmb{\sf {\qquad c =  \sqrt{169} }}} \\

{\longrightarrow \pmb{\sf {\qquad c= 13 }}}\\ \\

Therefore,

  • <u>The measure of the third side (c) is 13</u>
Gwar [14]2 years ago
3 0

Hey ! there

Answer:

  • <u>1</u><u>3</u><u> </u>is the answer .

Step-by-step explanation:

In this question we are provided with right angle triangle having <u>hypotenuse</u><u> </u><u>(</u><u> </u><u>longest </u><u>side </u><u>)</u><u> </u><u>=</u><u> </u><u>c </u><u>,</u><u> </u><u>perpendicular</u><u> </u><u>=</u><u> </u><u>5</u><u> </u><u>and </u><u>base </u><u>=</u><u> </u><u>1</u><u>2</u><u> </u><u>.</u> And we are asked to find the length of <u>missing side i.e. hypotenuse</u><u> </u>and if necessary we have to round it off to 2 decimal places.

We can find the missing side by using <u>Pythagorean</u><u> Theorem</u><u> </u><u>.</u> It states that sum of squares of perpendicular and base is equal to square in a right angle triangle that is ,

\:  \qquad  \: \qquad  \:  \underline{\boxed{ \frak{H {}^{2}  = P  {}^{2} + B {}^{2} }}}

<u>Where </u><u>,</u>

  • H refers to <u>Hypotenuse</u>

  • P refers to <u>Perpendicular</u>

  • B r refers to <u>Base</u>

<u>SOLUTION</u><u> </u><u>:</u><u> </u><u>-</u>

Substituting value of hypotenuse as c , perpendicular as 5 and base as 12 in formula :

\quad \longmapsto \qquad \: (c) {}^{2}  = (5) {}^{2}  + (12) {}^{2}

Squaring 5 and 12 :

\quad \longmapsto \qquad \:(c) {}^{2}  = 25 + 144

Adding 25 and 144 :

\quad \longmapsto \qquad \:(c) {}^{2}  = 169

Applying square root to both sides :

\quad \longmapsto \qquad \: \sqrt{(c) {}^{2} }  =  \sqrt{169}

On simplifying , We get :

\quad \longmapsto \qquad     \orange{\underline{\boxed{\frak{c = 13}}}} \quad \bigstar

  • <u>Henceforth</u><u> </u><u>,</u><u> </u><u>❝</u><u> </u><u>1</u><u>3</u><u> </u><u>❞</u><u> </u><u>is </u><u>the</u><u> </u><u>length </u><u>of </u><u>missing</u><u> </u><u>side </u><u>.</u>

<u>Verifying</u><u> </u><u>:</u><u> </u><u>-</u>

Now we are checking our answer by putting all values in formula . So ,

  • <u>(</u><u> </u><u>1</u><u>3</u><u> </u><u>)</u><u>²</u><u> </u>= ( 5 )² + ( 12 )²

  • 169 = 25 + 144

  • 169 = 169

  • L.H.S = R.H.S

  • Hence, Verified .

<u>Therefore</u><u> </u><u>,</u><u> </u><u>our </u><u>answer</u><u> is</u><u> correct</u><u> </u><u>.</u>

<h2><u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>

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Sophia has an ear infection. The doctor prescribes a course of antibiotics. Sophia is told to take 500 mg doses of the antibioti
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Answer:

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Step-by-step explanation:

Hello,

Sophia's doctor prescribed 500mg of drug for her every 12hrs.

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2. At the end of the second dose, she has

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