Given the equation of an hyperbola in the form:

Then the focus of the hyperbola is

Compute like this:

So the two focus points are

The vertices are given by the formula:

We deduce the two vertices of the given hyperbola:

since
Answer: A) 6x = 54; x = 9 times older
Step-by-step explanation:
9 x 6 = 54
You have to use trigonometry
Well 746÷40=18.65 so would that be 18?
(4b+3) (2b−5)
(4b+3) (2b+−5)
(4b) (2b) + (4b) (−5) +(3) (2b) +(3) (−5)
8b²−20b+6b−15.
= 8b²−14b−15.