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VikaD [51]
2 years ago
11

2.4 divided by 0.24 pllss help

Mathematics
1 answer:
ivann1987 [24]2 years ago
4 0

Answer:

your answer is 10 Goodluck

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(100 POINTS) Please help I'll give brainliest!<br> Image attached.
Norma-Jean [14]

#1

Area of base=1/2(2.8)(4.2)

  • 2.8(2.1)
  • 5.88in²

Volume:

  • Area of base×Height
  • 5.88(7)
  • 41.16in³

#2

Area of base

  • 6×1/2(7)(6.1)
  • 3(7)(6.1)
  • 128.1cm²

Volume:-

  • 128.1(14)
  • 1793.4cm³
4 0
2 years ago
Read 2 more answers
What is the solution to the equation 2x + 4 = 24? <br> x = 1 <br> x = 3 <br> x = 6 <br> x = 10
horsena [70]

Answer:

    x = 14

Step-by-step explanation:

1.1     Pull out like factors :

  2x - 20  =   2 • (x - 10)  

Equation at the end of step  1  :

Step  2  :

Equations which are never true :

2.1      Solve :    2   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

2.2      Solve  :    x-10 = 0  

Add  10  to both sides of the equation :  

                     x = 10  

One solution was found :

                  x = 10

4 0
3 years ago
Read 2 more answers
How to write 2.06 x 10 to the 10th power in standard form?
snow_tiger [21]

Answer:

20.60000000000

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
Which fraction is in reduced form?
kompoz [17]

Answer:

  C  5/13

Step-by-step explanation:

A fraction is written in reduced form if there are no common factors in the numerator and denominator. Since you know your multiplication tables, you can easily identify the common factors:

  A 20 = 5·4, so 4 is a common factor 4/(4·5) = 1/5

  B 6 = 2·3, 9 = 3·3, so 3 is a common factor (2·3)/(3·3) = 2/3

  C 13 is not a multiple of the prime number 5, so there are no common factors. 5/13 is a reduced fraction

  D 14 = 2·7, 21 = 3·7, so 7 is a common factor (2·7)/(3·7) = 2/3

8 0
4 years ago
A prize wheel is divided into 12 equally likely spaces labeled 1 to 12.
ikadub [295]

Answer:

Events E and F are independent.

Step-by-step explanation:

E = {multiple of 3}  = {3, 6, 9, 12}

P(E) = 4/12

F = {even number}  = {2, 4, 6, 8. 10, 12}

P(F) = 6/12

E and F = {even and multiple of 3} = {6, 12}

P(E∩F) = 2/12

In order for two events to be independent the following relationship must be true:

P(E)*P(F) = P(E\cap F)

Testing this property:

P(E)*P(F) = \frac{4}{12}*\frac{6}{12}=\frac{24}{144}=\frac{1}{6}    \\P(E\cap F) = \frac{2}{12}=\frac{1}{6} \\P(E)*P(F) = P(E\cap F)

The relationship holds true, thus events E and F are independent.

4 0
4 years ago
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