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meriva
4 years ago
5

How do you multiply 12x12 step by step?

Mathematics
2 answers:
geniusboy [140]4 years ago
8 0

Answer:

144

Step-by-step explanation:

 

 12

X12

------

 

If you are writing this problem out by hand, be sure that your numbers are lined up, like above.  This will help you in making sure that you solve each step of your problem properly.

 

First, start with the 12.  Multiply 12 by the "2" in the one's place, in the second number:

 

 12

X  2

-----

 

Begin by multiplying 2 X 2 first, in the "ones" column.

 

Do you have 2X2=4?  Great!  Put the 4 in the ones column, where your answer would go.

 

Next, multiply 2 times the 1 digit.  The 1 is actually a 10, because it is in the "tens" column.

 

2 X10=20

 

Place your 2 in the "tens" column--It should look like this...

 

 12

X  2

-----

 24

 

Since you are finished with the "ones" place, now you will work with the tens column.

 

put a zero under the 4 in 24.

 

then continue like this

 

 12

X12

-----

 24

120      because 12 X10=120

------

144      If you add 24 +120, you should have 144.

 

If you have a slightly different way of doing this problem, that's OK.  The point is to get the correct answer.

 

If you have a times table, you can check yourself.

 12 X12=144

Nata [24]4 years ago
3 0

Answer:

here you go

Step-by-step explanation:

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My guess is that you're expected to use 20 for the length of the 3rd side.

By Heron's formula, s = (7 +15 +20)/2 = 21

Area = √(21*(21 -7)*(21 -15)*(21 -20)) = √(21*14*6*1) = √1764 = 42 . . . . yd^2

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More directly,
.. Area = (1/2)*7*15*sin(127°) ≈ 41.928 . . . . yd^2

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The coordinates of the vertices of ∆PQR are P(-2,5), Q(-1,1), and R(7,3). Determine whether ∆PQR is a right triangle. Show your
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Given

∆PQR points are P(-2,5), Q(-1,1), and R(7,3)

Determine whether ∆PQR is a right triangle

To proof

As given ∆PQR points are P(-2,5), Q(-1,1), and R(7,3)

First find out the sides of triangle

FORMULA

Distance formula between two points

D^{2}= (x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}

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PR = \sqrt{(-1+2)^{2}+(1-5)^{2}  }

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Distance between two points  R(7,3) and P(-2,5)

RP =\sqrt{(-2-7)^{2} + (5-3)^{2}  }

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now show that ∆PQR is a right triangle

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Putting the value given above

(\sqrt{85}) ^{2} = \sqrt{17} ^{2} +\sqrt{68} ^{2}

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In the right triangle

HYPOTENUSE² = BASE² + PERPENDICULAR²

This is prove above

Hence ∆PQR is a right triangle

Hence proved










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