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2 years ago

X = 2y-2 4x-9 = 11 Step by step please

1 answer:

4 0

Answer x=5, y= 3.5

Find y by plugging the x value into the 2nd equation
4(2y-2) -9=11
8y - 8 - 9 =11 combine like terms
8y = 28 divide both sides by 8
y = 3.5

Now find x
Plug your y value into first equation
X = 2(3.5) -2
X= 7-2
X=5

You can check your work by putting your x or y values into the equations

For the first equation
5=2(3.5) -2
5=5

For the second equation
4(5) -9 = 11
20 - 9 = 11
11 =11

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3 years ago

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3 years ago

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Chris runs 6 miles in 50 minutes. At the same rate, how many miles would he run in 35 minutes?

Nataly_w [17]

You could either find how far Chris can run in 60 minutes, or write an equation of ratios:

x 35 min
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3 years ago

A vcr and tv were bought for 8000 each. The shopkeeper made a loss of 4 per cent on vcr and 8 per cent prophit on the tv. Find t

aleksley [76]

Answer:

2% gain

Step-by-step explanation:

We assume the shopkeeper bought the appliances at the indicated prices, and that gain is computed on the basis of that cost price.

Since the base cost is the same for each appliance, the percentages can be added directly to find the percentage gain on 8000. However, the shopkeeper's total outlay was 16000, not 8000, so the final gain percentage is half of that total.

gain percent = (-4% + 8%)/2 = 2%

_____

If you want to see the actual numbers:

Loss on VCR = 4% × 8000 = 320.

Gain on TV = 8% × 8000 = 640.

Total gain on 16000 is -320 +640 = 320. As a percentage, that is ...

320/16000 × 100% = 2%

7 0

3 years ago

Grace wove a potholder with an area of 80 square inches. The lengths and widths of the sides are whole numbers. Which dimensions

docker41 [41]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the question :

Grace wove a potholder with an area of 80 square inches. The lengths and widths of the sides are whole numbers. Which dimensions make the most sense for a potholder?

Since the Area of the potholder = 80 sq inch

And the dimension of the potholder ; length and width are integers ; Hence, possible dimensions could be ;

Area = length × width

80 = length × width

(80, 1), (40, 2), (20, 4), (10, 8), (16, 5)

Potholders are fabrics sewn from the purpose of being used to handle pots and other kitchen equipments.

Usually the dimension are usually close, hence, the most sensible dimension a potholder with an area of 80 sq inch could have is 8 by 10 or vice-versa.

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3 years ago