The difference in distance between Aero plane A and B is; 34.67 km
<h3>How to calculate bearing?</h3>
To get the bearing;
∠H = (115 - 90) + (270 - 203)
∠H = 92°
Then, we will use cosine rule to get the distance between both Planes A and B.
d_ab = √(18² + 29² - 2(18 * 29) * cos 92)
d_ab = √(324 + 841 + 36.435)
d_ab = 34.67 km
Read more about bearing at; brainly.com/question/22518031
#SPJ1
Answer:
D
Step-by-step explanation:
Put m+2 in place of 'x'
(m+2)^2 + 1 <======expand
m^2 + 4m + 4 + 1 =
m^2 + 4m + 5
Answer:33/9
Step-by-step explanation:
Log10(x+3)-Log10(x-3)=1
Log10((x+3)/(x-3))=1
(x+3)/(x-3)=10^1
(x+3)/(x-3)=10
Cross multiply
x+3=10(x-3)
Open brackets
x+3=10x-30
Collect like terms
10x-x=30+3
9x=33
Divide both sides by 9
9x/9=33/9
x=33/9
Answer:
Sry its long but if your to lazy to look thru it here is the answer= z = {-7, 8}
Step-by-step explanation:
Simplifying
z2 + -1z + -56 = 0
Reorder the terms:
-56 + -1z + z2 = 0
Solving:
-56 + -1z + z2 = 0
Solving for variable 'z'.
Factor a trinomial.
(-7 + -1z)(8 + -1z) = 0
Subproblem 1
Set the factor '(-7 + -1z)' equal to zero and attempt to solve:
Simplifying:
-7 + -1z = 0
Solving:
-7 + -1z = 0
Move all terms containing z to the left, all other terms to the right.
Add '7' to each side of the equation.
-7 + 7 + -1z = 0 + 7
Combine like terms: -7 + 7 = 0
0 + -1z = 0 + 7
-1z = 0 + 7
Combine like terms: 0 + 7 = 7
-1z = 7
Divide each side by '-1'.
z = -7
Simplifying:
z = -7
Subproblem 2
Set the factor '(8 + -1z)' equal to zero and attempt to solve:
Simplifying:
8 + -1z = 0
Solving:
8 + -1z = 0
Move all terms containing z to the left, all other terms to the right.
Add '-8' to each side of the equation.
8 + -8 + -1z = 0 + -8
Combine like terms: 8 + -8 = 0
0 + -1z = 0 + -8
-1z = 0 + -8
Combine like terms: 0 + -8 = -8
-1z = -8
Divide each side by '-1'.
z = 8
Simplifying:
z = 8
Solution
z = {-7, 8}
<h3>
<u>Answer:</u></h3>

<h3>
<u>Step-by-step explanation:</u></h3>
A figure is given to us in which we can see two triangles one is ∆ MPL and other is ∆MPN .
<u>Figure</u><u> </u><u>:</u><u>-</u><u> </u>



Hence by SAS congruence condition ,
Hence by cpct ( Corresponding parts of congruent triangles ) we can say that , LM = NM = 11 units .
<h3>
<u>Hence </u><u>the</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>LM</u><u> </u><u>is</u><u> </u><u>1</u><u>1</u><u> </u><u>units</u><u> </u><u>.</u></h3>