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sweet-ann [11.9K]
1 year ago
6

To prove the statement “If the dog does a trick, then the dog will get a treat” by proving its contrapositive, what statement sh

ould you prove? A) If the dog gets a treat, then the dog does a trick. B) If the dog does a trick, then the dog will not get a treat. C) If the dog does not do trick, then the dog will not get a treat. D) If the dog does not get a treat, then the dog will not do a trick.
Mathematics
1 answer:
katen-ka-za [31]1 year ago
6 0

Answer:C

Step-by-step explanation:

Contrapositive

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What is -12 = -3y? Can you pls help me
Rashid [163]

Answer:

y = 4

Step-by-step explanation:

-12= -3y

Divide both sides of the equation by

the same term

\frac{ - 12}{ - 3}  = \frac{  - 3y}{ - 3}

Simplify

Divide the numbers

Cancel terms that are in both the

merator and denominator

Move the variable to the left

y = 4

3 0
2 years ago
If y = x2 + 2x , find the value of y when x = 5
Arturiano [62]

Answer:

Step-by-step explanation:

Okay so you are gonna substitute x for 5 so the equations will look like y= (5)2+(5)2

So 10+10 = 20

So y=20

8 0
3 years ago
(name the intersection of the figure) pls help if ur good at geometry
Ipatiy [6.2K]

Answer:

im ok, i can help

Step-by-step explanation:

6 0
2 years ago
A circular swimming pool has a diameter of 40 meters. The depth of the pool is constant along west-east lines and increases line
Nataliya [291]

Answer:

Volume is 2000\pi\ m^{3}

Solution:

As per the question:

Diameter, d = 40 m

Radius, r = 20 m

Now,

From north to south, we consider this vertical distance as 'y' and height, h varies linearly as a function of y:

iff

h(y) = cy + d

Then

when y = 1 m

h(- 20) = 1 m

1 = c.(- 20) + d = - 20c + d              (1)

when y = 9 m

h(20) = 9 m

9 = c.20 + d = 20c + d                  (2)

Adding eqn (1) and (2)

d = 5 m

Using d = 5 in eqn (2), we get:

c = \frac{1}{5}

Therefore,

h(y) = \frac{1}{5}y + 5

Now, the Volume of the pool is given by:

V = \int h(y)dA

where

A = r\theta

A = rdr\ d\theta

Thus

V = \int (\frac{1}{5}y + 5)dA

V = \int_{0}^{2\pi}\int_{0}^{20} (\frac{1}{5}rsin\theta + 5) rdr\ d\theta

V = \int_{0}^{2\pi}\int_{0}^{20} (\frac{1}{5}r^{2}sin\theta + 5r}) dr\ d\theta

V = \int_{0}^{2\pi} (\frac{1}{15}20^{3}sin\theta + 1000) d\theta

V = [- 533.33cos\theta + 1000\theta]_{0}^{2\pi}

V = 0 + 2\pi \times 1000 = 2000\pi\ m^{3}

7 0
3 years ago
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sertanlavr [38]
In a parallelogram, opposite angles are congruent and consecutive angles are supplementary. 

3x - 15 = 2x + 24
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3 years ago
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