Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
I Got 0.01041666666 As An Answer <span />
9514 1404 393
Answer:
y = -3/8x -23/8
Step-by-step explanation:
The slope is found using the slope formula:
m = (y2 -y1)/(x2 -x1)
m = (-4 -(-1))/(3 -(-5)) = -3/8
Then the point-slope equation of the line is ...
y -k = m(x -h) . . . . line with slope m through point (h, k)
For m = -3/8 and (h, k) = (-5, -1), the line is ...
y +1 = -3/8(x +5)
In slope-intercept form, this is ...
y = -3/8x -23/8
Answer:
For me to answer this question I need to understand it, I really don't understand your question.
what is the question?
is there any diagram you left out in this "question" ?.
All I'm saying is that the question isn't clear.
thanks.
Answer:
y=25x+40.50 is not the equation of proportional relationship because if you were to graph the equation, the line would not go through the origin of the graph. You can tell beause of the y-intercept that is given in the equation, 40.50.
Step-by-step explanation:
