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8090 [49]
4 years ago
6

a. Do some research and find a city that has experienced population growth. Determine its population on January 1st of a certain

year. Write an exponential function to represent the city’s population, y, based on the number of years that pass, x after a period of exponential growth. Describe the variables and numbers that you used in your equation. b. Find another city whose population starts larger than the city in part (a), but that during this same time experienced population decline. Determine its population for January 1st of the same year you picked for part (a). Write an exponential function to represent the city’s population, y, based on the number of years that pass, x after a period of population decline. Describe the variables and numbers that you used in your equation. c. Explain the similarities and differences between your equations in (a) and (b). d. During what year will the population of city (a) first exceed that of city (b)? Show all of your work and explain your steps. e. During what year will the population of city (a) be at least twice the size of the population of city (b)? Show all of your work and explain your steps.
Mathematics
1 answer:
astraxan [27]4 years ago
3 0
Answer: You have a lot of work to do here. I can get you started in the right direction.

The growth equation that you are looking for will be in the form of:
 y = a(1 + b)^x.
A is the starting amount, b is the percent that you are increasing by and x is the number of years.

The declining equation that you are looking for will be in the form of:
y = a(1 - b)^x.
Again, a is the starting amount, be is the percent that you are decreasing by and x is the number of years.

I suggest you find an online graphing calculator and graph each equation. Then, you can answer the rest of your questions.

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Molly tried to evaluate 93\times5193×5193, times, 51 using partial products. Her work is shown below.
Mrac [35]

Since molly's solution tally's with the given solution, hence <em>Molly's solution is correct.</em>

Given the working on a partial product of 93 and 51 carried out by Molly as shown:

\begin{array}{llrr} &&93 \\ &&\underline{{}\times51} \\ &\blueD{\text{Step 1}}&\blueD{3}& \blueD{1\times3\text{ ones}}\\ &\greenD{\text{Step 2}}&\greenD{90}& \greenD{1\times 9\text{ tens}}\\ &\maroonD{\text{Step 3}}&\maroonD{150}& \maroonD{50\times 3\text{ ones}}\\ &\goldE{\text{Step 4}}&\underline{{}+\goldE{ 4{,}500}}& \goldE{50\times 9\text{ tens}}\\ &\purpleD{\text{Step 5}}&\purpleD{4{,}743}& \end{array}​

This partial product can also be solved as shown below:

93 \times 51 = (90+3)\times (50+1)

Applying the distributive law:

93 \times 51 = 90(50) + 90(1) + 3(50) + 3(1)\\93 \times 51 =4500 + 90 + 150 + 3\\93 \times 51 =4500+240+3\\93 \times 51 =4740+3\\93 \times 51 =4743

Since molly's solution tally's with the given solution, hence <em>Molly solution is correct.</em>

Learn more about partial product at: brainly.com/question/24716925

5 0
3 years ago
5 = ? ÷ 6 solve to find the unknown
zhuklara [117]
The answer would be 5 = 30 ÷ 6 or ? = 30
7 0
4 years ago
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Can someone please help me with this question? Thank you!
Goryan [66]

Answer: A

<u>Step-by-step explanation:</u>

\stackrel\frown{XY} ≅ \stackrel\frown{YZ}

⇒ ∠XOY ≅ ∠ZOY

\overline{XO} ≅ \overline{ZO} since they are both a radius

\overline{OY} ≅ \overline{OY} based on reflexive property

∴ ΔXOY ≅ ΔZOY by SAS

So, \overline{XY} ≅ \overline{ZY} by CPCTC

ZY = 10.2 is given

so, XY = 10.2 by substitution property


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4 years ago
70 decreased by 80% in math
pantera1 [17]
The answer for your math problem is 55.2. To get this, you do 70 times 0.80, which gives us 56. Then, subtract it by 0.80.
7 0
3 years ago
Solve for x. Rs/x =1/4 A. X=rs/4 B. X=4/rs C. X=1/4rs D. X=4rs
Burka [1]
The answer is b x=4/rs
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