Answer:
<h2>11.02</h2>
Explanation:
Predict the frequency of a+b+c progeny = 11.02
Step by step Explanation for all genes
a---8%----b---------24%--------c
Double cross overs = (RF at first locus × RF at second locus)/100
= 8 × 24 /100 =1.92
Double cross over progeny;
a b+ c =0.96
a+ b c+= 0.96
single cross over progeny;
RF = 8
SCO at first locus progeny= 8 -DCO progeny= 8- 1.92 = 6.08
a b+ c+= 3.04
a+ b c= 3.04
single cross over at second locus progeny---
RF = 24
SCO at second locus progeny= 24-DCO progeny= 24 - 1.92 = 22.02
abc+= 11.02;
a+b+c = 11.02;
Total recombinants = 1.92 + 6.08 + 22.02 = 30.02
Total nonrecombinants are = 100 - 30.02 = 69.98
abc = 34.99
a+b+c+ = 34.99.
Answer:
<em>The correct option is D) homologous structures</em>
Explanation:
In evolutionary studies, a homologous structure can be described s a similar structure which is present in different species. This is because these spices might have a common ancestor in the past. For example, the forelimbs of humans and bat. They perform different functions but their structure is similar. They are also derived from the same embryonic origin. These similarities show that the bats and humans might have shared a common ancestor in the past.
Codons are triplets of nucleotides found on mRNA which code for particular amino acids .
<h3>What are codons?</h3>
Codons are triplets of nucleotides found on mRNA which code for particular amino acids.
In an mRNA, strands, the first three codons, AUG code for the amino acid methionine.
Similarly, the codons GCA codes for alanine, CCA codes for proline.
In conclusion, given an mRNA strand, the amino acids coded by the codons can be deduced.
Learn more about codons at: brainly.com/question/7643068
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