Answer:
E) Either anaphase I or II
Explanation:
Failure of segregation of homologous chromosomes during anaphase I or failure of segregation of sister chromatids during anaphase II leads to the presence of the abnormal number of chromosomes in resultant gametes. In the given example, the egg mother cell with 48 chromosomes (24 pairs) would enter meiosis I but the failure of one pair of homologous chromosomes to segregate from each other followed by normal meiosis II would result in the formation of two gametes with one extra chromosome and two gametes with one less chromosome.
On the other hand, if the nondisjunction occurs at anaphase II of meiosis II, two normal gametes, one gamete with one extra chromosome and one gamete with one less chromosome will be formed. Therefore, nondisjunction at anaphase I or anaphase II would have resulted in the production of eggs with one extra chromosome.
Its making land fall on Saturday 2 p.m
LH and FSH by posterior pituitary while act on mature follicles to undergo ovulation. Estrogen and progesterone by ovaries and act on many things.
This solar energy conversion process is known as photosynthesis. ... At this time, the oxygen level was approximately 10% of its present atmospheric concentration. ... The presence of ozone enabled organisms to develop and live on the land.
The dominant gene takes over
