Question

Please help me, I need an answer as soon as possible.

Answer 1

Answer:

$\huge\boxed{\sf x = \pm \sqrt{7} }$

Step-by-step explanation:

Given function:

$f(x)=x^2-7$

We can also write it as:

$y =x^2-7$

x-intercept is the point where y = 0

Put y = 0 in the above equation

$0=x^2-7\\\\Add \ 7 \ to \ both\ sides\\\\7 = x^2\\\\Take \ sqrt \ on \ both \ sides\\\\\pm \sqrt{7} =x\\\\x = \pm \sqrt{7} \\\\\rule[225]{225}{2}$