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Goryan [66]
4 years ago
12

HEEYYA answer this ASAP ILL GIVE YOU 50 points

Mathematics
2 answers:
Nataliya [291]4 years ago
6 0

Answer:

A

Step-by-step explanation:

alexdok [17]4 years ago
3 0

Answer:

I'm pretty shure it A. based on which way the graph moves and the direction iit's going in

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9

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During a 12-hour period, the
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4 degrees every hour

Step-by-step explanation:

Since it was 48 degrees over a total of 12 hours we can do:

48 / 12 = 4 degrees.

It may be presented as -4 degrees since it is dropping in tempature therefore making it negative.

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Please help me <br> please help with just one question at least
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Step-by-step explanation:

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3 years ago
In October 1945, the Gallup organization asked 1,487 randomly sampled Americans, "Do you think we can develop a way to protect o
GalinKa [24]

Answer:

Yes. There is enough evidence to support the claim that the proportion of Americans feel the United States could develop a way to protect itself from atomic bombs in 1945 is significantly greater than 0.5.

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>In October 1945, the Gallup organization asked 1487 randomly sampled Americans, "Do you think we can develop a way to protect ourselves from atomic bombs in case other countries tried to use them against us?"</em><em> with 788 responding yes.</em><em> Did a majority of Americans feel the United States could develop a way to protect itself from atomic bombs in 1945? Use the α=0.05 level of significance.</em>

This is a hypothesis test for a proportion.

The claim is that the proportion of Americans feel the United States could develop a way to protect itself from atomic bombs in 1945 is significantly greater than 0.5.

Then, the null and alternative hypothesis are:

H_0: \pi=0.5\\\\H_a:\pi>0.5

The significance level is 0.05.

The sample has a size n=1487.

The sample proportion is p=0.53.

p=X/n=788/1487=0.53

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.5*0.5}{1487}}\\\\\\ \sigma_p=\sqrt{0.000168}=0.013

Then, we can calculate the z-statistic as:

z=\dfrac{p-\pi-0.5/n}{\sigma_p}=\dfrac{0.53-0.5-0.5/1487}{0.013}=\dfrac{0.03}{0.013}=2.288

This test is a right-tailed test, so the P-value for this test is calculated as:

\text{P-value}=P(z>2.288)=0.011

As the P-value (0.011) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the proportion of Americans feel the United States could develop a way to protect itself from atomic bombs in 1945 is significantly greater than 0.5.

8 0
3 years ago
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