Given:
Kelly purchased 5 containers of ice cream for a party.
Each container holds 8 cups of ice cream.
Her brother ate 2 cups of ice cream.
One serving of ice cream = 2/3 of a cup.
To find:
Number of servings of ice cream will be left for the party?
Solution:
We have,
1 container = 8 cups of ice cream
5 containers = 5×8 = 40 cups of ice cream
Her brother ate 2 cups of ice cream. So, remaining cups of ice cream is
cups
Now,
of a cup = 1 serving
1 cup = 
serving
38 cup = 
serving
= 
serving
= 57 serving
Therefore, 57 servings of ice cream will be left for the party.
Answer:
and 
Step-by-step explanation:
(a)
Expressing as a fraction
( divide numerator/ denominator by 2 )
= ← in simplest form
(b)
Expressing as a fraction
( divide numerator/ denominator by 10 )
= ← in simplest form
<h2>Information</h2>
$8.94 spent in total on groceries
Gallon of milk = $4.29
3 pounds of sliced turkey bought = ?
<h2>Explanation</h2>
Subtract the total amount spent on groceries with what items you have prices for (in this case the gallon of milk):
$8.94 (total spent) - $4.29 (gallon of milk) = $4.65 (for 3 pounds of sliced turkey)
Next, divide the price for 3 pounds of sliced turkey with however many pounds Bonita bought (in this case, 3 pounds):
$4.65 (total for 3 pounds of turkey) ÷ 3 (pounds of turkey) = $1.55 (per pound of turkey)
<h2>Solution</h2>
Each pound of turkey costs $1.55
The area of the shaded region can be found by subtracting the area of the inside rectangle from the outside rectangle
area of outside: 6 X 10y —> 60y
area of inside: 3 X 5x —> 15x
so the area of the shaded region is 60y-15x
the GCF is 15, so the factored form is: 15(4y-x)
1) No; you are incorrect. "0" is NOT a solution.
Plug in "0" for "x" ;
8*0² + 23 =? 823? ;
8*0 + 23 =? 823? ;
0 + 23 = ? 823 ? ; No! ; "0 + 23 = 23 " ; NOT "823" .
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2) The answers: x = 10, -10 ; or, write as: x = ± 10 .
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To solve:
GIven: 8x² + 23 = 823 ;
Subtract "23" from EACH SIDE of the equation:
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8x² + 23 - 23 = 823 - 23 ;
to get:
8x² = 800 ;
Now, divide EACH SIDE of the equation by "8" ;
8x² / 8 = 800 / 8 ;
to get: x² = 100 ;
Take the "square root" of EACH SIDE of the equation; to isolate "x" on one side of the equation; and to solve for "x" ;
√(x²) = √(100) ;
x = <span>± 10 .
The answers: x = 10, -10 ; or, write as: x = </span><span>± 10 .
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