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bezimeni [28]
2 years ago
6

5. Solve the system: x + 3y = -5 5x - 2y = 9

Mathematics
2 answers:
kow [346]2 years ago
8 0

Answer:

(1, - 2 )

Step-by-step explanation:

x + 3y = - 5 → (1)

5x - 2y = 9 → (2)

multiplying (1) by - 5 and adding to (2) will eliminate x

- 5x - 15y = 25 → (3)

add (2) and (3) term by term to eliminate x

0 - 17y = 34

- 17y = - 34 ( divide both sides by - 17 )

y = - 2

substitute y = - 2 into either of the 2 equations and solve for x

substituting into (1)

x + 3(- 2) = - 5

x - 6 = - 5 ( add 6 to both sides )

x = 1

solution is (1, - 2 )

goldenfox [79]2 years ago
5 0

Answer:

Step-by-step explanation:

x=1

y= -2

See step by step explanation below:

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What are the coordinates of the endpoints A'B after a reflection of segment AB over the line y = - x?
kupik [55]

Answer:

by reflection, if you mean swapped, then the answers are A'(1,-6) and B'(4,2)

i hope these are the answers you are looking for

Step-by-step explanation:

6 0
3 years ago
Determine the solution set of each equation
maks197457 [2]

A=x1 = -8,x2 =2, B=x1= -5,x2=5, C=y1 = -4, y2 =5, D=y 18 over 5

alternative form

y=3 3over 5, =3.6

And E=x1=0, x2 =2 over 3

Alternative form

x1=0, x2=0.666667.

question A

Solving steps:Solve the quadratic equation

x²+6x-16=0

write 6x as a difference

x2 +8x-2x-16=0

factor out x for the expression

xx(x+8)-2x-16=0

factor out -2 from the expression

xx(x+8)- 2(x+8)=0

factor out x+8 from the expression

(x+8)x(x- 2)=0

when the product of factors equals 0,at least one factor is 0

x+8=0

x - 2=0

solve the equation for x

x= -8

x - 2=0

solve the equation for x

x= -8

x =2

the equation has 2 solution

x1 = -8,X2 =2

answer is

x1 = -8,x2 =2

Or

Solving steps:Number of solution

x²+6x-16=0

Determine the number of solution using the

discriminant D =b²- 4ac

D =6²- 4x1x(-16)

simply the expression

D=100

Since D>0, the quadratic equation has 2 real solution

2 real solution

Answer is

2 real solution

Question B

Solving steps:Solve the quadratic equation

x²-25=0

Move the constant to the right-hand side and change its sign

x²=25

Take the square root of both sides of the equation and remember to use both positive and negative roots

x=+5

Write the solutions,one with a +sign and one with a -sign

x= -5

x=5

The equation has 2 solutions

x1= -5,x2=5

the answer is

x1= -5,x2=5

Or

Solving steps:Number of solution

x²-25=0

Determine the number of solutions using the discriminant D=b²- 4ac

D=0²- 4x1x(-25)

Simply the expression

D=100

Since D>0,the quadratic equation has 2real solutions

Answer is

2real solutions

answer of question C is

y1 = -4, y2 =5

Answer of question D is

y 18 over 5

alternative form

y=3 3over 5, =3.6

Answer of question E is

x1=0, x2 =2 over 3

Alternative form

x1=0, x2=0.666667

Please mark as brainiest

3 0
3 years ago
Read 2 more answers
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S_A_V [24]
C= 5(9*3b)
C= 5(9*12)
C= 5(108)
C=540
8 0
3 years ago
For a circle with a radius of 15 cm, what is the length of an arc intercepted by an angle measuring 120°?
slega [8]

Answer: 31.43 cm

Step-by-step explanation:

The length of an arc  is calculated using the formula:

\frac{theta}{360} X 2\pir

where : theta is the angle in degree

r = radius

If the angle is given in Radian , the length can be calculated using the formula:

L = r∅

Since , the angle is given in degree , we will use the first formula.

L = \frac{theta}{360} X 2\pir

L = \frac{120}{360} X 2 X π X 15

L = \frac{1}{3} X 2 X \frac{22}{7} X 15

L = \frac{660}{21}

L = 31.42857143

L ≈ 31.43 cm

5 0
3 years ago
What is the solution set of x2 + 5x + 1 = 0?
DerKrebs [107]

Answer:

\huge\boxed{\left\{-\dfrac{5+\sqrt{21}}{2};\ \dfrac{-5+\sqrt{21}}{2}\right\}}

Step-by-step explanation:

x^2+5x+1=0\\\\\text{Use the quadratic formula:}\\\\\text{For}\ ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\\text{if}\ \Delta < 0,\ \text{then the equation has no real solution}\\\text{if}\ \Delta=0,\ \text{then the equation has one real solution}\ x=\dfrac{-b}{2a}\\\text{if}\ \Delta>0,\ \text{then the equation has two real solution}\ x=\dfrac{-b\pm\sqrt{\Delta}}{2a}

\text{We have}\\\\a=1,\ b=5,\ c=1\\\\\Delta=5^2-4(1)(1)=25-4=21>0\\\\x=\dfrac{-5\pm\sqrt{21}}{2(1)}=\dfrac{-5\pm\sqrt{21}}{2}

3 0
3 years ago
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