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2 years ago

5. Solve the system: x + 3y = -5 5x - 2y = 9

Mathematics

2 answers:

kow [346]2 years ago

8 0

Answer:

(1, - 2 )

Step-by-step explanation:

x + 3y = - 5 → (1)

5x - 2y = 9 → (2)

multiplying (1) by - 5 and adding to (2) will eliminate x

- 5x - 15y = 25 → (3)

add (2) and (3) term by term to eliminate x

0 - 17y = 34

- 17y = - 34 ( divide both sides by - 17 )

y = - 2

substitute y = - 2 into either of the 2 equations and solve for x

substituting into (1)

x + 3(- 2) = - 5

x - 6 = - 5 ( add 6 to both sides )

x = 1

solution is (1, - 2 )

goldenfox [79]2 years ago

5 0

Answer:

Step-by-step explanation:

x=1

y= -2

See step by step explanation below:

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Graph a triangle (STU) and reflect it over the y-axis to create triangle ST'U'.

lukranit [14]

The x-coordinates of $\triangle S'T'U'$ will be the negation of the x-coordinates of $\triangle STU$

The line segment from S to the y-axis equals the line segment from S' to the y-axis. Similarly, the line segment from T to the y-axis equals the line segment from T' to the y-axis

See attachment for $\triangle STU$ and $\triangle S'T'U'$

In order to solve this question, I will make the following assumptions.

Assume that the coordinates of $\triangle STU$ are

$S = (4,5)$

$T = (5,9)$

$U=(3,8)$

Refer to attachment for illustrations

(1) Reflect $\triangle STU$ over y-axis and describe the transformation

To reflect $\triangle STU$ across the y-axis, the following rule must be followed

$(x,y) \to (-x,y)$

This means that:

$S = (4,5) \to S' = (-4,5)$

$T = (5,9) \to T' = (-5,9)$

$U=(3,8) \to U'=(-3,8)$

The description of the transformation is as follows:

Notice that the signs of the x-coordinates $\triangle STU$ and $\triangle S'T'U'$ of both triangles are different.

In other words, if the x-coordinate of one is positive, then the other will have a negative x-coordinate; and vice versa.

(2) Compare the segments and the line of reflection

To reflect across the y-axis means that the reflecting line is the y-axis, itself.

The distance between a point to the y-axis is the absolute value of the x-coordinate.

So, the distance between S and the y-axis is:

$S = |4| = 4$

The distance between S' and the y-axis is:

$S' = |-4| = 4$

We can conclude that the two line segments are equal.

This is the same for other point T and T' because of the formula used above.

From T and T' to the y-axis is:

$T =|5| =5$

$T' =|-5| =5$

Read more at:

brainly.com/question/938117

8 0

3 years ago

15y + 3 = 18y please show the work to this! (and explain If u like)

Pachacha [2.7K]

Answer:

y=1

Step-by-step explanation:

Move 18 to the other side. -3y=-3. y=1.

6 0

3 years ago

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I give Brainliest, Like all the time, and I really need this answered

Ugo [173]

Answer:

1: 8

Step-by-step explanation:

3 0

3 years ago

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Find the measure of the missing angles.

Karolina [17]

Answer:

angles b and c should be 153° each.

Step-by-step explanation:

We know the smaller angle is 27°. The other small angle, vertical to the 27° angle is also 27° because they are vertical angles. Along the lines, two angles should form 180°. So 180-27=153°. All together the angles should be 360°. Check your answer by doing 153+153+27+27=360. therefore the missing angles are both 153°

4 0

3 years ago

Select the correct answer

Tomtit [17]

Answer:

Step-by-step explanation:

The area for a triangle is

$A=\frac{1}{2}bh$

Our base is given as x, the height is given as 1 more than 6 times the base which looks like this: 6x + 1. We know that the area is 13, so filling in everything:

$13=\frac{1}{2} (6x+1)(x)$

We can get rid of the denominator of 2 by multiplying it on both sides to get:

$26=(6x+1)(x)$ and simplifying a bit:

$26=6x^2+x$

Now we can move over the 26 and put the expression into standard quadratic form by setting it equal to 0:

$6x^2+x-26=0$ which is choice C

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2 years ago