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svetoff [14.1K]
2 years ago
5

Polynomials & Factoring (4m+n)(m-2n) (2a-4b)(7a-2b) Thank you!

Mathematics
1 answer:
noname [10]2 years ago
7 0

Answer4

m

2

−

7

m

n

−

2

n

2

Step-by-step explanation:

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What is 6×9÷18+100-11+4
mojhsa [17]

6 × 9 ÷ 18 + 100 - 11 + 4

Use the order of operations to simplify:

  • Parentheses
  • Exponents
  • Multiplication
  • Division
  • Addition
  • Subtraction

6 × 9 ÷ 18 + 100 - 11 + 4

There are no parentheses or exponents, so multiplication comes first. Multiply 6 and 9.

54 ÷ 18 + 100 - 11 + 4

Next is division. Divide 54 by 18.

3 + 100 - 11 + 4

Finally, add and subtract from left to right.

103 - 11 + 4

92 + 4

96

<h3>Answer:</h3>

96

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3 years ago
Find the area of the shape shown below.<br> 12<br> 4
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Answer:

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If A is nonsingular, then (AT )-1 =(A-1) T . (a) Verify this theorem for 2 × 2 matrices
kipiarov [429]

Answer:

Verified

Step-by-step explanation:

Let the 2x2 matrix A be in the form of:

\left[\begin{array}{cc}a&b\\c&d\end{array}\right]

Where det(A) = ad - bc # 0 so A is nonsingular:

Then the transposed version of A is

A^T = \left[\begin{array}{cc}a&c\\b&d\end{array}\right]

Then the inverted version of transposed A is

(A^T)^{-1} = \frac{1}{ad - cb} \left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]

The inverted version of A is:

A^{-1} = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-b\\-c&d\end{array}\right]

The transposed version of inverted A is:

(A^{-1})^T = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]

We can see that

(A^T)^{-1} = (A^{-1})^T

So this theorem is true for 2 x 2 matrices

3 0
3 years ago
An exam has two probability problems, 1 and 2. If 37% of the students solved problem 1 and 12% of the students solved both probl
Zanzabum

Answer:

about 32%

Step-by-step explanation:

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3 years ago
To convert 2/3 into an equivalent fraction with a denominator of 18, we could multiply only the denominator of 2/3 by.
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Answer:

the answer is true

Step-by-step explanation:

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