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3 years ago

The length of Marshall's poster is 2 times its width. If the perimeter is 72 inches, what is the area of the poster?

Mathematics

2 answers:

Scorpion4ik [409]3 years ago

8 0

X= width
2x= length
2x+4x=72
6x=72
X=12
2(12)x(12)=24x12
The answer is 288 sq. in.

lesya [120]3 years ago

3 0

$x-width\\2x-length\\\\2x+2\cdot2x=72\\2x+4x=72\\6x=72\ \ \ \ |:6\\x=12\\\\2x=2\cdot12=24\\\\Area=24\cdot12=288\ in^2$

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Lemur [1.5K]

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1 year ago

Two weeks in a row, the golf course hosts a group of golfers. The second week had 10 more golfers than the first week. Use the d

Trava [24]

Answer:

Option A.

Step-by-step explanation:

From the first dot plot the given data set for week 1 is

62, 68, 68, 68, 69, 70, 70, 72, 72, 72, 75, 75, 76, 78, 78, 80, 80, 80, 89, 89

Divide the data in 4 equal parts.

(62, 68, 68, 68, 69), (70, 70, 72, 72, 72), (75, 75, 76, 78, 78), (80, 80, 80, 89, 89)

$Range=Maximum-Minimum=89-62=27$

$Median=\frac{72+75}{2}=73.5$

$Mean=\frac{\sum x}{n}=\frac{1491}{20}=74.55$

From the second dot plot the given data set for week 2 is

62, 68, 68, 68, 69, 70, 70, 72, 72, 72, 75, 75, 76, 78, 78, 80, 80, 80, 85, 86, 86, 86, 88, 88, 88, 88, 89, 89, 89, 89

Divide the data in 4 equal parts.

(62, 68, 68, 68, 69, 70, 70), 72, (72, 72, 75, 75, 76, 78, 78), (80, 80, 80, 85, 86, 86, 86), 88, (88, 88, 88, 89, 89, 89, 89)

$Range=Maximum-Minimum=89-62=27$

$Median=\frac{78+80}{2}=79$

$Mean=\frac{\sum x}{n}=\frac{2364}{30}=78.8$

The range for Week 1 is equal to the range for Week 2.

The median for Week 2 is more than the median for Week 1.

The mean for Week 2 is more than the mean for Week 1.

Therefore, the correct option is A.

6 0

2 years ago

Please help will give more then 5 points plus brainliest!

allsm [11]

Answer:

your answer would be A.

Step-by-step explanation:

your anwer would be A. beacuse you want to get to 180

and 116 and 64 = 180

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