The formula for the radius r in terms of x . and for the maximum areas is x=2/
+4
Given that,
y forms a circle of radius r
y=2r
r=y/2
(2-y)- forms Square Side x
(2-y) = 4x
x=(2-y)/4
Now Sum of Area's=Area of Square +Area of Circle
Sum = r² + x²
Substitute the r and x values in above equation,
A(y)= y²/4+(y-2)²/ 16
To maximize Area A(y)
A'(y)= 0
2y/4 + 2(y-2)/16 =0
y/2 + (y-2)/8 =0
y = 2/+4
Y max will be max, x to be maximum.
for maximum sum of areas,
x=2/+4
Hence,The formula for the radius r in terms of x . and for the maximum areas is x=2/+4
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1 ft = 12 in.
4 ft = 4 * 1 ft = 4 * 12 in. = 48 in.
4 ft 7 in. = 48 in. + 7 in. = 55 in.
4 ft 7 in. < 56 in.
Answer:
Step-by-step explanation:
A direct variation equation is of the form
y = kx,
where, in words, it reads "y varies directly with x" or "y varies directly as x". In order to use this as a model, we have to have enough information to solve for k, the constant of variation. The constant of variation is kind of like the slope in a straight line. It rises or falls at a steady level; it is the rate of change.
We have that a vet gives a dose of three-fifths mg to a 30 pound dog. If the dose varies directly with the weight of the dog, then our equation is
d = kw and we need to find k in order to have the model for dosing the animals.
Divide both sides by 1/30 to get k alone.
and
Our model then is
This means that for every pound of weight, the dog will get one-fiftieth of a mg of medicine.
Answer:
Step-by-step explanation:
Given
Required
Determine the sales price
First, we calculate the discount price
The sales price is then calculated by subtracting the discount price from the original price of the item
