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1 year ago

Can someone help me will give brainlist

Mathematics

1 answer:

Levart [38]1 year ago

6 0

Answer:

Step-by-step explanation:

If we roll a multiple of 5 we will get one of the following:

5, 10, 15 , 20.

None of these is a perfect square so they are mutually exlusive,

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Which statements accurately describe the function f(x) = 2(727)" ? Select three options.

MAVERICK [17]

Answer:

i cant see it its blorry

Step-by-step explanation:

4 0

3 years ago

A university law school accepts 7 out of every 11 applicants. If the school accepted 665 students, how many applications did the

Fittoniya [83]

Answer:

1,045 applications

Step-by-step explanation:

Create a proportion where x is the number of applications they received:

$\frac{7}{11}$ = $\frac{665}{x}$

Cross multiply and solve for x:

7x = 7315

x = 1045

So, they received 1,045 applications

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2 years ago

Noah saw some worms in his garden. He measured the length of each worm.

sergeinik [125]

Answer:

9 worms are longer than 3 inches

Step-by-step explanation:

you can just count how many are in in the rows after 3 and that is your answer

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2 years ago

Determine whether each expression is equivalent to 49^2t – 0.5.

vampirchik [111]

Answer:

None of the expression are equivalent to $49^{(2t - 0.5)}$

Step-by-step explanation:

Given

$49^{(2t - 0.5)}$

Required

Find its equivalents

We start by expanding the given expression

$49^{(2t - 0.5)}$

Expand 49

$(7^2)^{(2t - 0.5)}$

$7^2^{(2t - 0.5)}$

Using laws of indices: $(a^m)^n = a^{mn}$

$7^{(2*2t - 2*0.5)}$

$7^{(4t - 1)}$

This implies that; each of the following options A,B and C must be equivalent to $49^{(2t - 0.5)}$ or alternatively, $7^{(4t - 1)}$

A. $\frac{7^{2t}}{49^{0.5}}$

Using law of indices which states;

$a^{mn} = (a^m)^n$

Applying this law to the numerator; we have

$\frac{(7^{2})^{t}}{49^{0.5}}$

Expand expression in bracket

$\frac{(7 * 7)^{t}}{49^{0.5}}$

$\frac{49^{t}}{49^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{49^{t}}{49^{0.5}}$ becomes

$49^{t-0.5}}$

This is not equivalent to $49^{(2t - 0.5)}$

B. $\frac{49^{2t}}{7^{0.5}}$

Expand numerator

$\frac{(7*7)^{2t}}{7^{0.5}}$

$\frac{(7^2)^{2t}}{7^{0.5}}$

Using law of indices which states;

$(a^m)^n = a^{mn}$

Applying this law to the numerator; we have

$\frac{7^{2*2t}}{7^{0.5}}$

$\frac{7^{4t}}{7^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{7^{4t}}{7^{0.5}}$ = $7^{4t - 0.5}$

This is also not equivalent to $49^{(2t - 0.5)}$

C. $7^{2t}\ *\ 49^{0.5}$

$7^{2t}\ *\ (7^2)^{0.5}$

$7^{2t}\ *\ 7^{2*0.5}$

$7^{2t}\ *\ 7^{1}$

Using law of indices which states;

$a^m*a^n = a^{m+n}$

$7^{2t+ 1}$

This is also not equivalent to $49^{(2t - 0.5)}$

6 0

3 years ago

People show me your holiday spirit

LenaWriter [7]

Answer:

im the grinch

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers