Question

How do you find DE, Round to nearest 10th

Answer 1

Answer:  $DE\approx6.0$

Step-by-step explanation:

Observe in the figure given in the exercise that four right triangles are formed.

In this case you can use the following Trigonometric Identity to solve this exercise:

$cos\alpha=\frac{adjacent}{hypotenuse}$

From the figure you can identify that:

$\alpha =53\°\\\\hypotenuse=10\\\\adjacent=BE=DE$

Then, you can substitute values:

$cos(53\°)=\frac{DE}{10}$

The next step is to solve for DE in order to find its value. This is:

$10*cos(53\°)=DE\\\\DE=6.01$

Finally, rounding the result to the nearest tenth, you get that this is:

$DE\approx6.0$