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1 year ago

Which line is perpendicular to BC

Mathematics

1 answer:

Flauer [41]1 year ago

8 0

Answer:

Step-by-step explanation:

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What is the slope of the line passing through the points (−3, 4) and (4, −1)?

Igoryamba

Note:
The slope of a straight line passing through the points (x₁, y₁) and (x₂, y₂) is
$m= \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

The two given points are (-3,4) and (4,-1). Therefore the slope is
$m= \frac{-1-4}{4-(-3)} = \frac{-5}{7}$

Answer: $- \frac{5}{7}$

3 0

3 years ago

14.1-191<br> Is this the answer?

enyata [817]

I don’t know if this is what you’re asking but 14.1-191 = -176.9

4 0

2 years ago

Read 2 more answers

Convert solar days into minutes

Pepsi [2]

Answer:

1 Solar day = 86,400 seconds (SI Base Unit)

1 day = 1,440 minutes

Step-by-step explanation:

If need anymore help just ask I'm not really good at explaining but I'll try just comment haha ☺️

6 0

3 years ago

ASAP GIVING GOOD AMOUNT OF POINTS. I cannot fail my class or I will be sent to school again

svlad2 [7]

Answer

- 3/2

Step-by-step explanation:

Hope this helps:) if you need anynore help lmk!

6 0

2 years ago

Use spherical coordinates. evaluate (9 − x2 − y2) dv, where h is the solid hemisphere x2 + y2 + z2 ≤ 4, z ≥ 0.

avanturin [10]

In spherical coordinates, we have

$\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\rho\cos\varphi\end{cases}$

which gives volume element

$\mathrm dV=\mathrm dx\,\mathrm dy\,\mathrm dz=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta$

and so the triple integral is given by

$\displaystyle\iiint_H(9-x^2-y^2)\,\mathrm dV$
$=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/2}\int_{\rho=0}^{\rho=2}(9-\rho^2\sin^2\varphi)\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta$
$=\displaystyle2\pi\int_{\varphi=0}^{\varphi=\pi/2}\int_{\rho=0}^{\rho=2}(9\rho^2\sin\varphi-\rho^4\sin^3\varphi)\,\mathrm d\rho\,\mathrm d\varphi$
$=\dfrac{592\pi}{15}$

4 0

3 years ago