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timofeeve [1]
2 years ago
14

Which line is perpendicular to BC

Mathematics
1 answer:
Flauer [41]2 years ago
8 0

Answer:

a

Step-by-step explanation:

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4. refusal

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since defiance means not willing to cooperate

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Find an n-degree polynomial function with real coefficients satisfying the given condition.
kolezko [41]

In all cases, if f has real coefficients, then any complex roots occur in conjugate pairs, so if a+bi is a root, then so is a-bi. Also, by the fundamental theorem of algebra, if r_1,\ldots,r_n are roots to f, then for some constant a\in\mathbb R,

f(x)=a(x-r_1)\cdots(x-r_n)

1. If n=3 and f(3)=f(2i)=0, then

f(x)=a(x-3)(x-2i)(x+2i)=ax^3-3ax^2+4ax-12a

Given that f(-1)=50, we have

f(-1)=a(-1-3)(-1-2i)(-1+2i)=-20a=50\implies a=-\dfrac52

\implies\boxed{f(x)=-\dfrac52x^3+\dfrac{15}2x^2-10x+30}

2.

f(x)=a(x-4)(x-(-5+2i))(x-(-5-2i))=a x^3 + 6 a x^2 - 11 a x - 116 a

With f(2)=-636, we have

f(2)=a(2-4)(2+5-2i)(2+5+2i)=-106a=-636\implies a=6

\implies\boxed{f(x)=6x^3+36x^2-66x-696}

The rest are done in the same exact way.

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The answer should be (B)

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