after taking sqrt both side
3x/
3x/3y√2
x/√2y
multiply both denomenator and numerator by√2
√2x/2y
Answer is A
Which line is perpendicular to BC
1 answer:
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after taking sqrt both side
3x/
3x/3y√2
x/√2y
multiply both denomenator and numerator by√2
√2x/2y
Answer is A
Answer:
tanΘ = -
Step-by-step explanation:
Using the trigonometric identities
• sin²x + cos²x = 1, hence
cosx = ± √(1 - sin²x )
• tanx =
given sinΘ = , then
cosΘ = ±
Since Θ is in the second quadrant where cosΘ < 0, then
cosΘ = -
= - = -
tanΘ =
= × -
= -
