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stich3 [128]
3 years ago
15

The function h(t) = -16t2 + 48t + 28 models the height (in feet) of a ball where t is the time (in seconds).

Mathematics
1 answer:
Alex17521 [72]3 years ago
5 0

Answer:

64

Step-by-step explanation:

<em>[using calculus] </em>When the function h(t) reaches its maximum value, its first derivative will be equal to zero (the first derivative represents velocity of the ball, which is instantaneously zero). We have h'(t) = -32t + 48, which equals zero when t = 3/2 = 1.5. The ball therefore reaches its maximum height when t = 1.5. To find the maximum height, we need to find h(1.5), which is 64 feet.

<em>[without calculus] </em>This is a quadratic function, so its maximum value will occur at its vertex. The formula for the x-coordinate of the vertex is -b/2a, so the maximum value occurs when t = -48/(2*16), which is 1.5. The maximum height is h(1.5), which is 64 feet.

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