Answer:
i think x = 18.5
Step-by-step explanation:
6x-21 = 90°
6x = 90+21
6x = 111
x = 111/6
x = 18.5
Answer:
D) six hundred twenty-nine thousandths > six times one tenth plus three times one hundredth plus two times one thousandth
629000>8403 TRUE
Step-by-step explanation:
A) six times one tenth plus three times one hundredth plus two times one thousandth < six hundred twenty-nine thousandths
8,403.00
<629000 FALSE
B) six times one tenth plus three times one hundredth plus two times one thousandth = six hundred twenty-nine thousandths
8403= 629000 FALSE
C) six hundred twenty-nine thousandths < six times one tenth plus three times one hundredth plus two times one thousandth
629000<8403 FALSE
D) six hundred twenty-nine thousandths > six times one tenth plus three times one hundredth plus two times one thousandth
629000>8403 TRUE
Hope This Helps!!!
Answer:
multiply 5 x 4 = 20
multiply the dimensions of the lighter square
after all the multiplying you subtract your answers and you should get the VERY final answer
*don't add because it's area; just multiply
Answer: ![\sqrt[3]{125x^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125x%5E3%7D)
.
Step-by-step explanation: Given radical expression
![\sqrt[3]{5x} \times \sqrt[3]{25x^2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5x%7D%20%5Ctimes%20%5Csqrt%5B3%5D%7B25x%5E2%7D)
.
According to the product property of roots.
![\sqrt[n]{a} \times \sqrt[n]{b} = \sqrt[n]{a \times b}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%20%5Ctimes%20%5Csqrt%5Bn%5D%7Bb%7D%20%3D%20%5Csqrt%5Bn%5D%7Ba%20%5Ctimes%20b%7D)
On applying above rule, we get
![\sqrt[3]{5x} \times \sqrt[3]{25x^2} = \sqrt[3]{5x \times 25x^2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5x%7D%20%5Ctimes%20%5Csqrt%5B3%5D%7B25x%5E2%7D%20%3D%20%5Csqrt%5B3%5D%7B5x%20%5Ctimes%2025x%5E2%7D)
5 × 25 = 125 and
Therefore,
![\sqrt[3]{5x \times 25x^2}= \sqrt[3]{125x^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5x%20%5Ctimes%2025x%5E2%7D%3D%20%5Csqrt%5B3%5D%7B125x%5E3%7D)
<h3>So, the correct option would be second option
.</h3>
