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3 years ago

Find the GCF 18x three to the third power and 30x to the fifth power

Mathematics

1 answer:

Juliette [100K]3 years ago

8 0

18x^3 = 6x^3 (3)
30x^5 = 6x^3 (5x^2)

so
GCF = 6x^3

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A jeweler who buys a ring from a jewelry maker for $125 marked with the price by 135% for sale in the store what is the selling

siniylev [52]

Marked up by 135% means
new price=original price+(original price times markup) =125+(125 times 1.35)=293.75
tax
293.75 times 0.075=22.03125

293.75-22.03125=271.718 so aprox $271.72

selling price would be $271.72

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3 years ago

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The dimensions of a rectangle can be given by x+7 and x+2. If the area of the rectangle is 66 square inches, what are the dimens

Nadusha1986 [10]

to solve for the dimensions (x+7)(x+2)=66,

we can first use the foiling method to simplify the left side.

x^2 + 2x + 7x + 14 = 66

x^2 + 9x + 14 = 66

now, subtract 66 from both sides.

x^2 + 9x - 52 = 0

now, split this into two parentheses.

(x + 13)(x - 4)

since the root of -13 would give you negative values, x=4. This means that the dimensions of the rectangle are 11 and 6.

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2 years ago

Any complex number can be put into the form a+bi, where a and b are real numbers. (True and False).

Delvig [45]

The answer for that is definitely true. You're welcome ;).

6 0

2 years ago

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If f(x) = -5x - 1 and g(x) = x - 6 what is (f g) (7)

Cloud [144]

You have

$(f\circ g)(x) = f(g(x)) \implies (f\circ g)(7) = f(g(7))$

So, we have to compute g(7) and feed it as input to f(x). We have

$g(7)=7-6=1 \implies f(g(7))=f(1)=-5-1=-6$

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2 years ago

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A ball moves in a straight line has an acceleration of a(t) = 2t + 5. Find the position function of the ball if its initial velo

Vlad1618 [11]

Answer:

$s(t) = frac{t^3}{3} + \frac{5t^2}{2} - 3t + 12$

Step-by-step explanation:

Relation between acceleration, velocity and position:

The velocity function is the integral of the acceleration function.

The position function is the integral of the velocity function.

Acceleration:

As given by the problem, the acceleration function is $a(t) = 2t + 5$

Velocity:

$v(t) = \int a(t) dt = \int (2t+5) dt = \frac{2t^2}{2} + 5t + K = t^2 + 5t + K$

In which K is the constant of integration, which is the initial velocity. So K = -3 and:

$v(t) = t^2 + 5t - 3$

Position:

$s(t) = \int v(t) dt = \int (t^2 + 5t - 3) = \frac{t^3}{3} + \frac{5t^2}{2} - 3t + K$

In which K, the constant of integration, is the initial position. Since it is 12:

$s(t) = frac{t^3}{3} + \frac{5t^2}{2} - 3t + 12$

4 0

2 years ago