1/3 is the answer. Hope this helps
Let the value of the vehicle be described by the equation
V = a + bx
where x = number of years since purchase
a,b are constants.
When x = 0, V = $7500. Therefore
a + b*0 = 7500
a = 7500
When x = 7, V = $500. Therefore
7500 + 7b = 500
7b = 500 -7500 = -7000
b = -7000/7 = -1000
The equation is
V = 7500 - 1000x
The slope of this equation is the depreciation rate, and it is -$1000 per year.
Answer: $1000 depreciation per year.
0.003 is 1/10 of 0.03.
Just multiply the 0.003 by 10 and you'll get the answer.
Answer:
Step-by-step explanation:
[1] 3x - 4y = -24
[2] -x - 16y = -52
Graphic Representation of the Equations :
-4y + 3x = -24 -16y - x = -52
Solve by Substitution :
// Solve equation [2] for the variable x
[2] x = -16y + 52
// Plug this in for variable x in equation [1]
[1] 3•(-16y+52) - 4y = -24
[1] - 52y = -180
// Solve equation [1] for the variable y
[1] 52y = 180
[1] y = 45/13
// By now we know this much :
x = -16y+52
y = 45/13
// Use the y value to solve for x
x = -16(45/13)+52 = -44/13
Solution :
{x,y} = {-44/13,45/13}
Sh(2x) = (e^2x + e^-2x)/2
<span>Thus the integral becomes </span>
<span>Int[e^3x*(e^2x + e^-2x)/2] = Int[(e^5x + e^x)/2] </span>
<span>= e^5x/10 + e^x/2 + C
</span>=(1/10)(e^5x) + (1/2)(e^x) + C
