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Alex_Xolod [135]
3 years ago
9

the perimeter of a triangle is 59 in. The longest side is 11in. longer than the medium side, and the medium side is 3in longer t

han the shortest side. find the length of each side of the triangle
Mathematics
1 answer:
ollegr [7]3 years ago
3 0
We're gonna call x the length of the shortest side.  The medium side is 3 longer than the shorter side, and the longest side is 14 longer than the shortest (11 + 3 = 14):

Perimeter = shortest side + medium side + longest side
59 = (x) + (x + 3) + (x + 14)
59 = 3x + 17
3x = 42
x = 14

Shortest side  =  14
Medium side  =  17
Longest side  =  28
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Answer:

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Step-by-step explanation:

The legs of an isosceles triangle both measure 10 inches

Since the triangle is a right triangle,

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a² + b² = c²

a = 10 inches, b = 10 inches and (c) is the hypotenuse whose value we don't know.

So; 10² + 10² = c²

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c = \sqrt{200} = 14.1421356237 inches

The hypotenuse is 14.1421 inches (answer rounded off to four decimal values)

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4 years ago
Sherry swam the length of the community pool 4 times. The pool is 32 feet long.   What is the total distance Sherry swam, measur
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3 years ago
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Answer:

(1) 12 boxes (2) 1173  points

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4 years ago
If the domain of G(x)=4-3x is -5,4,and 7 how do I find the range?
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4 years ago
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X should equal 12.5

You have to split the isosceles acute triangle in the middle of the polygon down the middle, and find what the now right isosceles tringle is. Since we already know that there's a 50 degress and a 90 degress there all you have to do is add those two numbers together and subtract from 180. Thena after you've done that you just need to multiply 40 by 2 and bata bing, bata boom you have 80 degress as your top, you already have a 50 and the last one has to be 50. Divide 50 by 4 and you get 12.5

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4*x= 50

x=12.5

7 0
3 years ago
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