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pshichka [43]
3 years ago
6

Suppose you roll not die. Find the Probability of not rolling an even number

Mathematics
1 answer:
irina [24]3 years ago
7 0
I think you mean roll a die. To do this you would find the number of non-even numbers and divide that number by the total amount of numbers on the die. On a normal six-sided die these numbers would be 1,3,and 5, so your probability of not rolling an even number would be 50%
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Please help!!! i’ll give brainliest.
S_A_V [24]

Answer:

quadrilateral ABCD is not congruent to quadrilateral KLMN. quadrilateral ABCD cannot be mapped onto quadrilateral KLMN through a series of rotations, reflections or translations.

7 0
3 years ago
helpppp it’s also not C
svlad2 [7]
Correct answer in this scenario would be D
6 0
3 years ago
What is the range of f(x)=4^x
Lerok [7]

Answer:

y>0

all positive real numbers

Step-by-step explanation:

the range is the output values

this will always be greater than 0

Range : y>0



7 0
2 years ago
Read 2 more answers
A consensus forecast is the average of a large number of individual analysts' forecasts. Suppose the individual forecasts for a
zaharov [31]

Answer:

a) P(X>3.5)=P(\frac{X-\mu}{\sigma}>\frac{3.5-\mu}{\sigma})=P(Z>\frac{3.5-5}{1.2})=P(z>-1.25)

And we can find this probability using the complement rule:

P(z>-1.25)=1-P(z

b) P(X

And we can find this probability uing the normal standard table:

P(z

c) P(3.5

And we can find this probability with this difference:

P(-1.25

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-1.25

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(5,1.2)  

Where \mu=5 and \sigma=1.2

We are interested on this probability

P(X>3.5)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>3.5)=P(\frac{X-\mu}{\sigma}>\frac{3.5-\mu}{\sigma})=P(Z>\frac{3.5-5}{1.2})=P(z>-1.25)

And we can find this probability using the complement rule:

P(z>-1.25)=1-P(z

Part b

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability uing the normal standard table:

P(z

Part c

P(3.5

And we can find this probability with this difference:

P(-1.25

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-1.25

3 0
3 years ago
I need help with the question l, can you help.please thank you​
inessss [21]
If you can send an image of the beginning of the question, I’d be glad to help. You didn’t show enough info for me to get an answer
4 0
2 years ago
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