Explain how to solve this problem:
1 answer:
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A) For f(-1) we use the part of the piecewise function for when x < 0 because -1 < 0. Plug in -1 for x:
2(-1) + 3 = 1
b) For f(0), we use the part for when x
0.
4(0) + 5 = 5
c) For f(2) we use the part for when x 0.
4(2) + 5 = 13
2(-1) + 3 = 1
b) For f(0), we use the part for when x
4(0) + 5 = 5
c) For f(2) we use the part for when x
4(2) + 5 = 13