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yan [13]
3 years ago
9

I need help on this question

Mathematics
2 answers:
Alenkinab [10]3 years ago
6 0
Answer : I’ll say it’s B.
If it’s wrong sorry. I tried.
Reika [66]3 years ago
6 0
The correct answer would be B. If you divide by three on triangle A’B’C’ you would get triangle ABC
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What is the value of y in the solution to the system of equations?x y = 12x – 3y = –30<br>y=-6x+18​
Oksana_A [137]

Answer:

x=4/5

y=66/5

Use the system of equation to solve for the variables

3 0
3 years ago
Answer this please......
Brrunno [24]

Answer:

1). Option A

2). Option B

Step-by-step explanation:

Question 1

Rule for the dilation of a point by a scale factor 'k' is given by the rule,

(x, y) → (kx, ky)

By this rule image of point A when dilated by the scale factor = 1.25,

A(-12, -8) → A'[(-12 × 1.25), (-8 × 1.25)]

              → A'(-15, -10)

Option A will be the answer.

Question 2

Scale factor = \frac{\text{Dimension or one side of the image}}{\text{Dimension or one side of the preimage}}

From the figure attached,

Scale factor = \frac{F'E'}{FE}

                    = \frac{4}{14}

                    = \frac{2}{7}

Therefore, rule for the dilation of ABC to form image triangle A'B'C' will be,

(x, y) → (\frac{2}{7}x, \frac{2}{7}y)

Option B will be the answer.

8 0
3 years ago
A garden that is 5ft by 6ft has a walkway 2 ft wide around it. Determine the values of x and y and find the amount of fencing ne
Rudik [331]

Answer:

you will need 30 ft of fencing to determine this

Step-by-step explanation:

so all you need to do is just multiply 6 and 5 then you get 30 hoped this helped bro

8 0
4 years ago
Read 2 more answers
The radius of a circle is 21 in. What is the precise distance around the circle?
Afina-wow [57]

Answer:

IT IS REALLY 31

Step-by-step explanation:

7 0
3 years ago
Find the equation of the line that passes through the point (7,5) and is perpendicular to the line 2x - 3y=6
balu736 [363]
(7,5);\ \ \ \  2x - 3y=6 \ \ / subtract \ 2x \ from \ each \ side \\ \\-3y = -2x + 6\ \ /  divide \    each \term \ by \ (-3) \\ \\ y =  \frac{2} {3}x -2\\ \\ The \ slope \ is :m _{1} =  \frac{ 2}{3} \\ \\ If \ m_{1} \ and \ m _{2} \ are \ the \ gradients \ of \ two \ perpendicular \\ \\ lines \ we \ have \\\\\ m _{1}*m _{2} = -1

\frac{2}{3}\cdot m_{2}=-1\ \ / \cdot (\frac{3}{2})\\\\m_{2}=-\frac{3}{2}\\\\Now \ your \ equation \ of \ line \ passing \ through \ (7,5) would \ be: \\ \\ y=m_{2}x+b \\ \\5=-\frac{3}{2}\cdot 7  + b \\ \\ 5= -\frac{21}{2}+b\\ \\b=5+\frac{21}{2} \\ \\b= \frac{10}{2}+\frac{21}{2}\\ \\b= \frac{31}{2}\\\\b=15.5 \\ \\ y = -\frac{3}{2}x +15.5
8 0
3 years ago
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