Answer:
![\mathbf{\dfrac{\pi}{6}[5 \sqrt{5}-1]}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cdfrac%7B%5Cpi%7D%7B6%7D%5B5%20%5Csqrt%7B5%7D-1%5D%7D)
Step-by-step explanation:
Given that:
The surface area (S.A) 
Hence the S.A is of form z = f(x,y)
Then the S.A can be represented with the equation

where :
D = cylinder 
In polar co-ordinates:
D = {(r, θ): 0≤ r ≤ 1, 0 ≤ θ ≤ 2π)
Similarly,
and 
Therefore;



![= [\theta]^{2 \pi}_{0} \dfrac{1}{8}\times \dfrac{2}{3}\begin {bmatrix} (1+4r^2)^{\dfrac{3}{2}}\end {bmatrix}^1_0](https://tex.z-dn.net/?f=%3D%20%5B%5Ctheta%5D%5E%7B2%20%5Cpi%7D_%7B0%7D%20%5Cdfrac%7B1%7D%7B8%7D%5Ctimes%20%5Cdfrac%7B2%7D%7B3%7D%5Cbegin%20%7Bbmatrix%7D%20%281%2B4r%5E2%29%5E%7B%5Cdfrac%7B3%7D%7B2%7D%7D%5Cend%20%7Bbmatrix%7D%5E1_0)
![= 2 \pi \times \dfrac{1}{12}[5^{\dfrac{3}{2}} - 1]](https://tex.z-dn.net/?f=%3D%202%20%5Cpi%20%5Ctimes%20%5Cdfrac%7B1%7D%7B12%7D%5B5%5E%7B%5Cdfrac%7B3%7D%7B2%7D%7D%20-%201%5D)
![\mathbf{=\dfrac{\pi}{6}[5 \sqrt{5}-1]}](https://tex.z-dn.net/?f=%5Cmathbf%7B%3D%5Cdfrac%7B%5Cpi%7D%7B6%7D%5B5%20%5Csqrt%7B5%7D-1%5D%7D)
Answer:
4
Step-by-step explanation:
Look at the tenths place to round.
4 and below, round down.
5 and above, round up.
In this case, it’s 5 so round up.
3.50 -> 4
Answer:
The correct option is B.
Step-by-step explanation:
According to AAS congruence rule, two triangles are congruent if two angles and a non included side are congruent to corresponding angles and side of another triangle.
We need two angles and a non included side, to use AAS postulate.
In option A, two sides and their inclined angle are congruent, therefore these triangles are congruent by SAS postulate and option A is incorrect.
In option B, two angles and a non included side are congruent, therefore these triangles are congruent by AAS postulate and option B is correct.
In option C, two angles and their included side are congruent, therefore these triangles are congruent by ASA postulate and option C is incorrect.
In option D, all sides are congruent, therefore these triangles are congruent by SSS postulate and option D is incorrect.
Answer:
4 hours
Step-by-step explanation:
If the circumference of the circular garden =63 yards
Circumference of a Circle =2πr=πd (d=diameter)
Therefore:
πd= 63
diameter of the circular garden =63/3.14=20 yards
If he digs at a rate of 5 yards per hour, the time required to dig across the garden will be:
20 yards/5 yard per hours = 4 hours
It will take him 4 hours to dig across the circular garden.
C = 2m^2 + m
D = 2 - 6m + 2m^2
2C = 2(2m^2 + m) = 4m^2+2m
2D = 2(2-6m+2m^2) = 4-12m+4m^2
2C - 2D =
4m^2+2m-(4-12m+4m^2) =
4m^2+2m-4+12m-4m^2 =
0m^2 + 14m -4 =
14m - 4