To solve this problem, let us first assign some
variables. Let us say that:
x = pigs
y = chickens
z = ducks
From the problem statement, we can formulate the
following equations:
1. y + z = 30 --->
only chicken and ducks have feathers
2. 4 x + 2 y + 2 z = 120 --->
pig has 4 feet, while chicken and duck has 2 each
3. 2 x + 2 y + 2 z = 90 --->
each animal has 2 eyes only
Rewriting equation 1 in terms of y:
y = 30 – z
Plugging this in equation 2:
4 x + 2 (30 – z) + 2 z = 120
4 x + 60 – 2z + 2z = 120
4 x = 120 – 60
4 x = 60
x = 15
From the given choices, only one choice has 15 pigs. Therefore
the answers are:
She has 15 pigs, 12 chickens, and 18 ducks.
Steps to solve:
3(5x - 8) = 6x + 39
~Distribute left side
15x - 24 = 6x + 39
~Add 24 to both sides
15x = 6x + 63
~Subtract 6x to both sides
9x = 63
~Divide 9 to both sides
x = 7
Best of Luck!
<span>216,000,000
</span><span>2.2 × 10 to the 3rd power = 2.2 * 10^3 = 2,200
</span>3.1 × 10 to the 7th power = 3.1 * 10^7 = 31,000,000
<span>310,000
Increasing order:
</span>2,200 , 310,000 , 216,000,000 , 31,000,000
So increasing order with original numbers:
2.2 × 10 to the 3rd power, 310,000, <span>216,000,000, 3.1 × 10 to the 7th power</span>
Answer:
Ummm I dont know what subject it is so i will guess 2.3?
Step-by-step explanation:
I'm Sorry im really useless
