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Masja [62]
2 years ago
12

Identify the unit rate in the graph. ILL GIVE BRAINLY

Mathematics
2 answers:
OverLord2011 [107]2 years ago
7 0

Answer:

D

Step-by-step explanation:

They wanted to hang Adam's and Hancock as traitors.

lukranit [14]2 years ago
7 0

Answer:

Step-by-step explanation:

Because Samuel Adams Was The Leader of The American Revolution and Opposed The British Parliament's Taxes; John Hancock was rich but didn't pay taxes. They were both deemed traitors.

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Given: RHOM is a rhombus. Prove: MRH = MOH<br><br> Need help for a friend
blsea [12.9K]
A= given
b= congruent side
c= transitive property
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6 0
3 years ago
- The taxi company charges $0.75 per mile
gladu [14]

Answer: y = .75x + 3

Step-by-step explanation:

y = .75x + 3

a) rate of change is .75x

b) initial value 3

c) independent is .75x

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6 0
3 years ago
(X^4)-(45x^2)+324 what are the zeroes? And how many turning points?
dmitriy555 [2]

Zeroes:

We must solve

x^4-45x^2+324=0

To do so, we define the auxiliary variable t=x^2. The equation becomes

t^2-45t+324=0

The quadratic formula yields the solutions

t=9,\quad t=36

Substituting back t=x^2 gives

x^2=9 \iff x=\pm 3,\quad x^2=36 \iff x=\pm 6

So, the zeroes are -6, -3, 3, 6.

Turning points:

Turning points are points where a function stops being increasing to become decreasing, or vice versa. Since functions are increasing when their first derivative is positive and decreasing when it's negative, turning points are points where the first derivative is zero.

We have

f(x)=x^4-45x^2+324 \implies f'(x)=4x^3-90x

If we set the derivative to be zero, we have

4x^3-90x=0 \iff x(4x^2-90)=0

So, the derivative is zero if x=0 or

4x^2=90 \iff 2x^2=45 \iff x^2=\dfrac{45}{2}\iff x=\pm\sqrt{\dfrac{45}{2}}

6 0
3 years ago
Whats the surface area
Lena [83]

Answer:

20 units^2

Step-by-step explanation:

5 x 4

20

3 0
3 years ago
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I have a question on a homework problem. Select the function that represents an arithmetic sequence.
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7 ig because I mean if you take a look at the problem
4 0
3 years ago
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