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3 years ago

Identify the unit rate in the graph. ILL GIVE BRAINLY

Mathematics

2 answers:

OverLord2011 [107]3 years ago

7 0

Answer:

Step-by-step explanation:

They wanted to hang Adam's and Hancock as traitors.

lukranit [14]3 years ago

7 0

Answer:

Step-by-step explanation:

Because Samuel Adams Was The Leader of The American Revolution and Opposed The British Parliament's Taxes; John Hancock was rich but didn't pay taxes. They were both deemed traitors.

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The La Jolla tide pools are 67.5 miles from the SLMS. A map shows that 2 inches = 15 miles. What distance is SLMS from the tide

Gwar [14]

Answer:

Step-by-step explanation:

because you have to divide by 15's

5 0

3 years ago

Read 2 more answers

A spinner has three unusual sections: red, yellow, and blue.. The table shows the results of Nolan’s spins. Find the probability

Anika [276]

Answers:

Red = 1/3
Yellow = 7/15
Blue = 1/5

====================================================

Explanation:

Add up all the frequencies in the table to see that there are 120+168+72 = 360 spins total.

Of those 360 spins, 120 of them land on red. The probability of landing on red is 120/360 = (120*1)/(120*3) = 1/3
Since 168 land on yellow, this means the probability of landing on yellow is 168/360 = (24*7)/(24*15) = 7/15
Lastly, we have 72 occurrences of blue out of 360 total spins. The probability of landing on blue is 72/360 = (72*1)/(72*5) = 1/5

4 0

3 years ago

10x^3 y^-5 z^-2 if x=3 y=2 and z=5 express your answer as a reduced fraction

sineoko [7]

Answer:

$\large\boxed{\dfrac{27}{80}}$

Step-by-step explanation:

Put x = 3, y = 2 and z = 5 to the given expression $10x^3y^{-5}z^{-2}$ :

$10(3^3)(2^{-5})(5^{-2})\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\=\dfrac{10(27)}{(2^5)(5^2)}=\dfrac{270}{(32)(25)}=\dfrac{270}{800}=\dfrac{27}{80}$

7 0

3 years ago

How to solve this trig

n200080 [17]

Hi there!

To find the Trigonometric Equation, we have to isolate sin, cos, tan, etc. We are also given the interval [0,2π).

First Question

What we have to do is to isolate cos first.

$\displaystyle \large{ cos \theta = - \frac{1}{2} }$

Then find the reference angle. As we know cos(π/3) equals 1/2. Therefore π/3 is our reference angle.

Since we know that cos is negative in Q2 and Q3. We will be using π + (ref. angle) for Q3. and π - (ref. angle) for Q2.

Find Q2

$\displaystyle \large{ \pi - \frac{ \pi}{3} = \frac{3 \pi}{3} - \frac{ \pi}{3} } \\ \displaystyle \large \boxed{ \frac{2 \pi}{3} }$

Find Q3

$\displaystyle \large{ \pi + \frac{ \pi}{3} = \frac{3 \pi}{3} + \frac{ \pi}{3} } \\ \displaystyle \large \boxed{ \frac{4 \pi}{3} }$

Both values are apart of the interval. Hence,

$\displaystyle \large \boxed{ \theta = \frac{2 \pi}{3} , \frac{4 \pi}{3} }$

Second Question

Isolate sin(4 theta).

$\displaystyle \large{sin 4 \theta = - \frac{1}{ \sqrt{2} } }$

Rationalize the denominator.

$\displaystyle \large{sin4 \theta = - \frac{ \sqrt{2} }{2} }$

The problem here is 4 beside theta. What we are going to do is to expand the interval.

$\displaystyle \large{0 \leqslant \theta < 2 \pi}$

Multiply whole by 4.

$\displaystyle \large{0 \times 4 \leqslant \theta \times 4 < 2 \pi \times 4} \\ \displaystyle \large \boxed{0 \leqslant 4 \theta < 8 \pi}$

Then find the reference angle.

We know that sin(π/4) = √2/2. Hence π/4 is our reference angle.

sin is negative in Q3 and Q4. We use π + (ref. angle) for Q3 and 2π - (ref. angle for Q4.)

Find Q3

$\displaystyle \large{ \pi + \frac{ \pi}{4} = \frac{ 4 \pi}{4} + \frac{ \pi}{4} } \\ \displaystyle \large \boxed{ \frac{5 \pi}{4} }$

Find Q4

$\displaystyle \large{2 \pi - \frac{ \pi}{4} = \frac{8 \pi}{4} - \frac{ \pi}{4} } \\ \displaystyle \large \boxed{ \frac{7 \pi}{4} }$

Both values are in [0,2π). However, we exceed our interval to < 8π.

We will be using these following:-

$\displaystyle \large{ \theta + 2 \pi k = \theta \: \: \: \: \: \sf{(k \: \: is \: \: integer)}}$

Hence:-

For Q3

$\displaystyle \large{ \frac{5 \pi}{4} + 2 \pi = \frac{13 \pi}{4} } \\ \displaystyle \large{ \frac{5 \pi}{4} + 4\pi = \frac{21 \pi}{4} } \\ \displaystyle \large{ \frac{5 \pi}{4} + 6\pi = \frac{29 \pi}{4} }$

We cannot use any further k-values (or k cannot be 4 or higher) because it'd be +8π and not in the interval.

For Q4

$\displaystyle \large{ \frac{ 7 \pi}{4} + 2 \pi = \frac{15 \pi}{4} } \\ \displaystyle \large{ \frac{ 7 \pi}{4} + 4 \pi = \frac{23\pi}{4} } \\ \displaystyle \large{ \frac{ 7 \pi}{4} + 6 \pi = \frac{31 \pi}{4} }$

Therefore:-

$\displaystyle \large{4 \theta = \frac{5 \pi}{4} , \frac{7 \pi}{4} , \frac{13\pi}{4} , \frac{21\pi}{4} , \frac{29\pi}{4}, \frac{15 \pi}{4} , \frac{23\pi}{4} , \frac{31\pi}{4} }$

Then we divide all these values by 4.

$\displaystyle \large \boxed{\theta = \frac{5 \pi}{16} , \frac{7 \pi}{16} , \frac{13\pi}{16} , \frac{21\pi}{16} , \frac{29\pi}{16}, \frac{15 \pi}{16} , \frac{23\pi}{16} , \frac{31\pi}{16} }$

Let me know if you have any questions!

3 0

3 years ago

Need help on this plzz

Aleksandr [31]

I do believe that it's one of the bisected ones. bisect is the line that splits the middle and D is definitely wrong. So that should narrow it down. So I would go with A or B. Sorry if I didn't help much but it's better than having no clue.

5 0

3 years ago