The correct answer is B). 6
Radius of inscribed circle of triangle HJK is 6 unit
Step-by-step explanation:
As shown in figure,
The triangle HJK has In-circle or inscribed circle of radius PL(or PM or PN)
Since, PL and PM is radius of same in-circle,
PL = PM
Given that PL=3x+4 and PM =6x-14
3x+4=6x-14
3x=18
x=6
Thus, The correct answer is B). 6
Answer:
Step-by-step explanation:
Since angle ABD is 133 degrees and the sum of the angles in a triangle is 180 degrees, it means that
m∠ DAB + 133 + 22 = 180
m∠ DAB = 180 - 155 = 25 degrees
Also, ∆ ADC is an isosceles triangle because two of its sides are equal. It also means that the base angles are equal. Thus,
m∠ A = m∠ B
Therefore,
m∠ A + m∠ B + angle D = 180
m∠ A + m∠ B = 180 - 22 × 2
m∠ A + m∠ B = 180 - 44 = 136
m∠ A = m∠ B = 136/2 = 68 degrees
m∠ CAB + m∠ DAB = m∠ A
Therefore,
m∠ CAB = 68 - 25 = 43 degrees
Since ∆ ABC is isosceles, then
m∠ CAB = m∠ ACB
m∠ ACB = 43 degrees
m∠ ABC = 180 - (43 × 2) = 180 - 86
m∠ ABC = 94 degrees
m∠ BCD = 68 - m∠ ACB
m∠ BCD = 68 - 43 = 25 degrees
Answer:
20
Step-by-step explanation:
224÷4 = 56+40 = 96÷2 = 48+12 = 60÷3 = 20
Answer:
C = -30
Step-by-step explanation:
C = 5/9 (F - 32)
C = 5/9 ( - 22 - 32)
C = 5/9 ( -54)
C = -30
Answer:
L = 10.64°
Step-by-step explanation:
From the given information:
In triangle JKL;
line k = 9.6 cm
line l = 2.7 cm; &
angle J = 43°
we are to find angle L = ???
We can use the sine rule to determine angle L:
i.e
Using Pythagoras rule to find j
i,e
j² = k² + l²
j² = 9.6²+ 2.7²
j² = 92.16 + 7.29
j² = 99.45
j = 9.97
∴
