At constant temperature, if the volume of the gas decreased to the given value, the pressure increases to 2.16atm.
<h3>What is Boyle's law?</h3>
Boyle's law simply states that "the volume of any given quantity of gas is inversely proportional to its pressure as long as temperature remains constant.
Boyle's law is expressed as;
P₁V₁ = P₂V₂
Where P₁ is Initial Pressure, V₁ is Initial volume, P₂ is Final Pressure and V₂ is Final volume.
Given the data in the question question;
- Initial volume of the gas V₁ = 682mL = 0.682L
- Initial pressure of the gas P₁ = 1.33atm
- Final volume of the gas V₂ = 0.419L
- Final pressure of the gas P₂ = ?
P₁V₁ = P₂V₂
P₂ = P₁V₁ / V₂
P₂ = ( 1.33atm × 0.682L) / 0.419L
P₂ = 0.90706Latm / 0.419L
P₂ = 2.16atm
Therefore, at constant temperature, if the volume of the gas decreased to the given value, the pressure increases to 2.16atm.
Learn more about Boyle's law here: brainly.com/question/1437490
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