Question

What volume, in milliliters, of distilled water is needed to make a 9.24 M solution of HCl using 190.0 Grams of HCL? (1 mol HCl = 36.46g HCl)

Answer 1

Answer : The volume of solution needed is, 563.9 mL

Explanation : Given,

Molarity of solution = 9.24 M

Mass of HCl = 190.0 g

Molar mass of $HCl$ = 36.46 g/mole

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

$\text{Molarity}=\frac{\text{Mass of }HCl\times 1000}{\text{Molar mass of }HCl\times \text{Volume of solution (in mL)}}$

Now put all the given values in this formula, we get:

$9.24M=\frac{190.0g\times 1000}{36.46g/mole\times \text{Volume of solution}}$

$\text{Volume of solution}=563.9mL$

Therefore, the volume of solution needed is, 563.9 mL