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3 years ago

A student solves the following equation and determines that the solution is -2. Is the student correct? Explain.

Mathematics

2 answers:

77julia77 [94]3 years ago

6 0

Answer:0 i got zero

Step-by-step explanation:

Elena L [17]3 years ago

4 0

Answer:

Edg

Step-by-step explanation:

No, the student did not check the solution to the derived equation in the original equation.

No, a possible solution is a = –2, but it does not check in the original equation because it makes two of the denominators equal to zero.

No, a = –2 is an extraneous solution, and there is no solution to the original rational equation.

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3 years ago

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4 years ago

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3 years ago

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PilotLPTM [1.2K]

Answer:

A) 2.58

B) 1.96

C) 1.65

Step-by-step explanation:

A hypothesis used to test that

$H_o : \mu = 10$

against the alternatives $H1 : \mu$ not equal to 10

if null hypothesis is true, then distribution of test statics follow

$Zo = \frac{\bar x - \mu}{\frac{\sigma}{\sqrt{n}}}$

for two sided alternatives hypothesis $( H1: \mu \neq 7)$ , then P value is

$P = 2[1- \phi(\left | Zc \right |)]$ (1)

a)significance level $\alpha = 0.01$

from 1 eq we get

$\pi (\left | Zc \right |) = P(Zo$

Therefore $\left | Zc \right | = 2.58$ FROM Z TABLE

B) significance level $\alpha = 0.05$

from 1st equation we get

$\pi (\left | Zc \right |) = P(Zo < \left | Zc \right |) = 1 - \frac{0.05}{2} = 0.975$

Therefore $\left | Zc \right | = 1.96$ FROM Z TABLE

C) significance level $\alpha = 0.10$

from 1 eq we get

$\pi (\left | Zc \right |) = P(Zo$

Therefore $\left | Zc \right | = 1.65$ FROM Z TABLE

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4 years ago