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Mathematics

2 answers:

goldfiish [28.3K]2 years ago

7 0

Answer:

u = 3

Step-by-step explanation:

${u}^{3} = 27$

${3}^{3} = 27$

$3 \times 3 \times 3 = 27$

aleksley [76]2 years ago

5 0

Answer:

u = 3 , − 3 − 3 i √ 3 /2 , − 3 + 3 i √ 3 /2

Step-by-step explanation:

Factor using difference of cubes and set each factor equal to 0 .

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Help ASAP (Math) will give brainiest and points!!

nordsb [41]

Answer:

$2.17 \times 10^{-1}$

Step-by-step explanation:

$(7 \times 10 ^{-6}) + 0.26 - (5 \times 10^{-2}) = \frac{7}{10^3} + \frac{26}{10^2}-\frac{5}{10^2}$

$= \frac{7 + (26 \times 10) - ( 5 \times 10)}{10^3}\\\\=\frac{7 + 260 - 50 }{10^3}\\\\=\frac{217}{10^3}\\\\= 2.17 \times 10^2 \times 10^{-3}\\\\= 2.17 \times 10^{-1}$

3 0

2 years ago

Find the equation of the line that passes through (1, -1) and is parallel to

daser333 [38]

keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

$2x+y-3=0\implies y=\stackrel{\stackrel{m}{\downarrow }}{-2} x+3 \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

so we're really looking for the equation of a line with a slope of -2 and that passes through (1 , -1)

$(\stackrel{x_1}{1}~,~\stackrel{y_1}{-1})\qquad \qquad \stackrel{slope}{m}\implies -2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1)}=\stackrel{m}{-2}(x-\stackrel{x_1}{1}) \\\\\\ y+1=-2x+2\implies y=-2x+1$