The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>
The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using

Substitute the known values in the above equation

Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
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Answer:
Use a calculator solved :)))
Step-by-step explanation:
Answer:
The correct option is 1. The area of cross section area is 48 mm².
Step-by-step explanation:
From the find it is noticed that the cross section is a rectangle with length 4 mm and width is 12 mm.
The area of a rectangle is the product of its dimensions.

Where, l is length of the rectangle and w is width of the rectangle.
The area of cross section is


Therefore the area of cross section area is 48 mm². Option 1 is correct.
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Answer:
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Step-by-step explanation: