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Aneli [31]
2 years ago
11

Answer this volume based Question. I will make uh brainliest + 50 points​

Mathematics
1 answer:
Harlamova29_29 [7]2 years ago
8 0

Answer:

\huge{\purple {r= 2\times\sqrt[3]3}}

\huge 2\times \sqrt [3]3 = 2.88

Step-by-step explanation:

  • For solid iron sphere:
  • radius (r) = 2 cm (Given)

  • Formula for V_{sphere} is given as:

  • V_{sphere} =\frac{4}{3}\pi r^3

  • \implies V_{sphere} =\frac{4}{3}\pi (2)^3

  • \implies V_{sphere} =\frac{32}{3}\pi \:cm^3

  • For cone:
  • r : h = 3 : 4 (Given)
  • Let r = 3x & h = 4x

  • Formula for V_{cone} is given as:

  • V_{cone} =\frac{1}{3}\pi r^2h

  • \implies V_{cone} =\frac{1}{3}\pi (3x)^2(4x)

  • \implies V_{cone} =\frac{1}{3}\pi (36x^3)

  • \implies V_{cone} =12\pi x^3\: cm^3

  • It is given that: iron sphere is melted and recasted in a solid right circular cone of same volume
  • \implies V_{cone} = V_{sphere}

  • \implies 12\cancel{\pi} x^3= \frac{32}{3}\cancel{\pi}

  • \implies 12x^3= \frac{32}{3}

  • \implies x^3= \frac{32}{36}

  • \implies x^3= \frac{8}{9}

  • \implies x= \sqrt[3]{\frac{8}{3^2}}

  • \implies x={\frac{2}{ \sqrt[3]{3^2}}}

  • \because r = 3x

  • \implies r=3\times {\frac{2}{ \sqrt[3]{3^2}}}

  • \implies r=3\times 2(3)^{-\frac{2}{3}}

  • \implies r= 2\times (3)^{1-\frac{2}{3}}

  • \implies r= 2\times (3)^{\frac{1}{3}}

  • \implies \huge{\purple {r= 2\times\sqrt[3]3}}
  • Assuming log on both sides, we find:

  • log r = log (2\times \sqrt [3]3)

  • log r = log (2\times 3^{\frac{1}{3}})

  • log r = log 2+ log 3^{\frac{1}{3}}

  • log r = log 2+ \frac{1}{3}log 3

  • log r = 0.4600704139

  • Taking antilog on both sides, we find:

  • antilog(log r )= antilog(0.4600704139)

  • \implies r = 2.8844991406

  • \implies \huge \red{r = 2.88\: cm}

  • \implies 2\times \sqrt [3]3 = 2.88
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The general form of a least square regression line is:

y=\alpha +\beta x

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<em>y</em> = dependent variable

<em>x</em> = independent variable

<em>α</em> = intercept

<em>β</em> = slope

(a)

The formula to compute intercept and slope is:

\begin{aligned}        \alpha  &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2}  \\\beta &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2}        \end{aligned}

The values of ∑<em>X</em>, ∑<em>Y</em>, ∑<em>XY</em> and ∑<em>X</em>² are computed in the table below.

Compute the value of intercept and slope as follows:

\begin{aligned}        \alpha &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} =             \frac{ 68.6 \cdot 55 - 15 \cdot 218.9}{ 6 \cdot 55 - 15^2} \approx 4.662 \\ \\\beta &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2}        = \frac{ 6 \cdot 218.9 - 15 \cdot 68.6 }{ 6 \cdot 55 - \left( 15 \right)^2} \approx 2.709\end{aligned}

The least-square regression line is:

y=4.662+2.709x

(b)

For the year 2007 the value of <em>x</em> is 10.

Compute the value of <em>y</em> for <em>x</em> = 10 as follows:

y=4.662+2.709x

  =4.662+(2.709\times10)\\=4.662+27.09\\=31.752\\\approx 31.8

Thus, the number of households using online banking at the beginning of 2007 is 31.8.

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