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MrMuchimi
3 years ago
15

Help guys show your solution and answer the question​

Mathematics
1 answer:
vichka [17]3 years ago
7 0

Answer:

Step-by-step explanation:

A)1) I found the LCM, by multiplying the common term with highest power and multiplying all the uncommon terms

2) I factored the trinomials into binomials that satisfies (i) the sum of two numbers is (-7) (ii)  Product of the two numbers is 6

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Kelly was building a bed for her dollhouse. She used her bed, which is 4 feet × 6 feet, as a guide. She scaled down the dimensio
galben [10]
Hey! 
So when there is a scale factor you would always multiply it with the original dimensions, even if it wasn't a fraction.
so 4 time 1/5 is 0.8
and 6 times 1/5 is 1.2
so the dimensions of the model bed is 0.8 foot by 1.2 feet
Your answer is A!
Hope this helps!
4 0
3 years ago
Read 2 more answers
Three-fourths of a cake remains after a birthday party. Each serving is 1/16 of the cake. How many servings of the cake remain?
Novay_Z [31]

Answer:

3/4 = 12/16

Step-by-step explanation:

3 x 4 = 12

4 x 4 = 16

12/16 :)

6 0
2 years ago
Suppose you toss a coin four times. What is the probability that you get heads on the second, third, and fourth losses?​
Svetach [21]

Answer:

3:4

Step-by-step explanation:

probability = what wanted : total outcome

                 =  3 heads : 4 tosses

                = 3 : 4

4 0
3 years ago
Write a linear equation in standard form that crosses (4, -3) and (-2, 9): 
kirill115 [55]
Slope =(9+3)/(-2-4) = 12/-6 = -2
Y+3 = -2 (×-4)  => y=-2×+5
D is the line asked
Slope: -1/3 
D: y-6 = -1/3 (×-3) or y= -1/3× + 7
8 0
3 years ago
Please help me with this question
san4es73 [151]

Step-by-step explanation:

Given: f'(x) = x^2e^{2x^3} and f(0) = 0

We can solve for f(x) by writing

\displaystyle f(x) = \int f'(x)dx=\int x^2e^{2x^3}dx

Let u = 2x^3

\:\:\:\:du=6x^2dx

Then

\displaystyle f(x) = \int x^2e^{2x^3}dx = \dfrac{1}{6}\int e^u du

\displaystyle \:\:\:\:\:\:\:=\frac{1}{6}e^{2x^3} + k

We know that f(0) = 0 so we can find the value for k:

f(0) = \frac{1}{6}(1) + k \Rightarrow k = -\frac{1}{6}

Therefore,

\displaystyle f(x) = \frac{1}{6} \left(e^{2x^3} - 1 \right)

5 0
3 years ago
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