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KIM [24]
3 years ago
11

Two vertices of an equilateral triangle are located at (2, 0) and (–2, –3). What is the triangle’s perimeter?​

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
3 0

Answer:

15

Step-by-step explanation:

one side is equal to 5. So 5 ×3

You might be interested in
Is y =3/4x +2 And -6x+8y=16 parallel or coincident
Rudiy27

Answer:

parallel

Step-by-step explanation:

y=3/4x+2

Multiply the equation by 8:

8y=6x+16

(8y-6x)=16

and you can clearly see that they're same

4 0
3 years ago
What is the result of isolating y2 in the equation below?
lyudmila [28]
STEP-BY-STEP SOLUTION:

( x + 4 )^2 + y^2 = 22

x^2 + 2 × x × 4 + 4^2 + y^2 = 22

x^2 + 8x + 16 + y^2 = 22

y^2 = 22 - x^2 - 8x - 16

y^2 = - x^2 - 8x + 6

FINAL ANSWER:

Therefore, the answer is:

D. y^2 = - x^2 - 8x + 6

Please mark as brainliest if you found this helpful! :)
Thank you <3
6 0
3 years ago
The courtyard outside East Middle School is in the shape of a rectangle and half-circle.
Nadya [2.5K]

Answer:

The correct option is the third one counting from the top. (5892 m^2)

Step-by-step explanation:

First, we need to remember that:

For a rectangle of length L and width W, the area is:

A = L*W

For a circle of diameter D, the area is:

A = pi*(D/2)^2

Where pi = 3.14

In the image, we can see a rectangle and half a circle, the total area of the image will be equal to the area of the rectangle plus the area of the half circle.

In the image, we can see a rectangle of length L = 100m and width W = 50m

Then the area of the rectangle is:

A = 100m*50m = 5000m^2

And we can see that for the half-circle the diameter is D = 50m

Note that the area of a half-circle is half of the area of a complete circle, then the area of that half-circle is:

A = (1/2)*(3.14*(50m/2)^2) = 981.25 m^2

If we add these two areas we get:

Total area =  5000m^2 + 981.25 m^2 = 5981.25 m^2

If we round it up, we get:

Total area = 5982 m^2

The correct option is the third one counting from the top.

8 0
2 years ago
Explain how to determine the zeros of f(x)=(x+3)(x-1)(x-8)
spin [16.1K]

Answer:

x=-3,  x=1,  x=8

Step-by-step explanation:

When you have to find the zero of an equation like (x+3) all you have to do is solve for x.

x+3=0           equal the equation to zero

x+3-3=0-3    cancel out 3

x=-3              answer


If you have to find the zero of an equation like f(x)=-2x^2 - 5x + 7 then you would have to factor the equation.

7*-2=-14   multiply

-7 & 2   find the two numbers that when multiplied =14 and when added = -5

(2x^2 + 2)  (-7x + 7)  replace -5 with -7 & 2

-2x (x - 1)   -7 (x - 1)   factor

(x - 1)   (-2x - 7)    rewrite

1st: x - 1 = 0

          x = 1 : Answer

2nd: -2x - 7= 0

        -2x - 7 + 7 = 0 + 7

        -2x = 7

        -2x / -2 = 7 / -2

          x = 7 / -2 : Answer





7 0
3 years ago
Read 2 more answers
If g(r) =2(r-1), Find g(10)
garri49 [273]

Answer:

g(r) = 18

Step-by-step explanation:

Substitute 10 into r

g(10) = 2( (10) -1)

        = 2(9)

        = 18

7 0
3 years ago
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