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Marta_Voda [28]
2 years ago
14

Substitute

Mathematics
1 answer:
Tju [1.3M]2 years ago
4 0

Answer:

\Large\boxed{\sf{x=-1, y=1}}

<h3>(-1,1)</h3>

Step-by-step explanation:

Isolate the term of x and y from one side of the equation.

<h3>-x+6y=7 and 6x+2y=-4</h3>

-x+6y=7= x=-7+6y

First, you have to substitute of x=-7+6y.

\Longrightarrow: \sf{6\left(-7+6y\right)+2y=-4}

Solve.

Use the distributive property.

<u>Distributive property:</u>

⇒ A(B+C)=AB+AC

⇒ A(B-C)=AB-AC

6(-7+6y)

Multiply expand.

6*-7=-42

6*6y=36y

-42+36y+2=-4

Add.

36y+2=38y

\Longrightarrow: \sf{-42+38y=-4}}

First, add by 42 from both sides.

-42+38y+42=-4+42

Solve.

38y=38

Divide by 38 from both sides.

38y/38=38/38

Solve.

38/38=1

<h3><u>y=1</u></h3>

For x=-7+6y

Substitute of y=1.

x=-7+6*1

Use the order of operations.

PEMDAS stands for:

  • Parentheses
  • Exponents
  • Multiply
  • Divide
  • Add
  • Subtract

-7+6*1

Do multiply.

6*1=6

-7+6

Add/subtract the numbers from left to right,

-7+6=-1

<h3><u>x=-1</u></h3>

  • <u>Therefore the final answer is x=-1 and y=1.</u>

I hope this helps, let me know if you have any questions.

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