Instantaneous rate of change = S'(r) = 8πr
S'(8) = 8π(8) = 64π
Therefore, the instantaneoud rate of change of the <span>surface area with respect to the radius r at r = 8</span> is 64π
16 positive and 26 negative.......16 - 26 = -10 <==
Hi! Your answer is q = -9
Please see an explanation for a better and clear understanding to your problem.
Any questions about my answer and explanation can be asked through comments! :)
Step-by-step explanation:
Since we want to solve for q-term. That means we are going to isolate q-term.

We can add 4 and 9 together.

Because we want to know the value of q. That means we have to isolate q-term by subtracting both sides by 13.

We are reaching to the final step where we divide the whole equation by 3.

Finally, the solution for this equation is q = -9. But what if you are not certain or sure about the answer? Let's check it out!
To check the answer, simply substitute q = -9 in the equation.

Notice that the equation is true for q = -9. Hence, we can conclude that the solution for this equation is q = -9.
Hope this helps!
Answer:
70
Step-by-step explanation:
verticle angles are congruent (the same) so if 1 is 110 than 4 is 110. also same side interior angles are supplementary (equal to 180) meaning 6 is 70. If verticle angles are congreunt then 7 also equals 70
2 i hope this helps ok bye