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Darya [45]
3 years ago
15

A baker has 88 muffins. He fills large boxes that hold 9 muffins each.Then, he puts the leftover muffins in a small box. How man

y muffins are in the small box.
Mathematics
1 answer:
V125BC [204]3 years ago
6 0

Answer:

7

Step-by-step explanation:

You might be interested in
PLEASE SOMEONE HELP ME I WILL MARK YOU AS BRAINLIEST IF YOU CAN EXPLIAN THE PROCEDURES YOU DID anyways too guys can you please g
iren2701 [21]
If you are finding the sample space see if it is biased or not. and if it population then find the experimental or theoretical.
3 0
3 years ago
Let X denote the length of human pregnancies from conception to birth, where X has a normal distribution with mean of 264 days a
Kaylis [27]

Answer:

Step-by-step explanation:

Hello!

X: length of human pregnancies from conception to birth.

X~N(μ;σ²)

μ= 264 day

σ= 16 day

If the variable of interest has a normal distribution, it's the sample mean, that it is also a variable on its own, has a normal distribution with parameters:

X[bar] ~N(μ;σ²/n)

When calculating a probability of a value of "X" happening it corresponds to use the standard normal: Z= (X[bar]-μ)/σ

When calculating the probability of the sample mean taking a given value, the variance is divided by the sample size. The standard normal distribution to use is Z= (X[bar]-μ)/(σ/√n)

a. You need to calculate the probability that the sample mean will be less than 260 for a random sample of 15 women.

P(X[bar]<260)= P(Z<(260-264)/(16/√15))= P(Z<-0.97)= 0.16602

b. P(X[bar]>b)= 0.05

You need to find the value of X[bar] that has above it 5% of the distribution and 95% below.

P(X[bar]≤b)= 0.95

P(Z≤(b-μ)/(σ/√n))= 0.95

The value of Z that accumulates 0.95 of probability is Z= 1.648

Now we reverse the standardization to reach the value of pregnancy length:

1.648= (b-264)/(16/√15)

1.648*(16/√15)= b-264

b= [1.648*(16/√15)]+264

b= 270.81 days

c. Now the sample taken is of 7 women and you need to calculate the probability of the sample mean of the length of pregnancy lies between 1800 and 1900 days.

Symbolically:

P(1800≤X[bar]≤1900) = P(X[bar]≤1900) - P(X[bar]≤1800)

P(Z≤(1900-264)/(16/√7)) - P(Z≤(1800-264)/(16/√7))

P(Z≤270.53) - P(Z≤253.99)= 1 - 1 = 0

d. P(X[bar]>270)= 0.1151

P(Z>(270-264)/(16/√n))= 0.1151

P(Z≤(270-264)/(16/√n))= 1 - 0.1151

P(Z≤6/(16/√n))= 0.8849

With the information of the cumulated probability you can reach the value of Z and clear the sample size needed:

P(Z≤1.200)= 0.8849

Z= \frac{X[bar]-Mu}{Sigma/\sqrt{n} }

Z*(Sigma/\sqrt{n} )= (X[bar]-Mu)

(Sigma/\sqrt{n} )= \frac{(X[bar]-Mu)}{Z}

Sigma= \frac{(X[bar]-Mu)}{Z}*\sqrt{n}

Sigma*(\frac{Z}{(X[bar]-Mu)})= \sqrt{n}

n = (Sigma*(\frac{Z}{(X[bar]-Mu)}))^2

n = (16*(\frac{1.2}{(270-264)}))^2

n= 10.24 ≅ 11 pregnant women.

I hope it helps!

6 0
3 years ago
Is (2,2) a solution to this system of equations? x + 2y = 6 3x + 4y = 14
babymother [125]

Answer:

No

Step-by-step explanation:

(2,2) isn't but  (6 1/2, -2) is because that is where they intercept

5 0
3 years ago
If y varies directly as​ x, and y=8 when x=3​, find y when x=15.
Crank

Answer:

y=40

Step-by-step explanation:

The formula for Direct Variation is y=kx or k=y/x. In this case I would use k=y/x. If you're y is 8 and x is 3, this means that K=8/3. Using this, we know that X=15. We have to find a Y value so that the fraction with an x of 15 simplified is 8/3. To do this you would write 8/3 and y/15. Now cross multiply to get 3y=120. Divide by 3 to get y=40. View my attachment for the work!

8 0
3 years ago
Combine as indicated by the signs. 8-y/3y + y+2/9y - 2/6y
Taya2010 [7]

Answer:

26 + y

----------

   9y


Step-by-step explanation:

Your using parentheses here would remove a great deal of ambiguity.  Looking at your 8-y/3y + y+2/9y - 2/6y, I have interpreted it to mean:

(8-y)/3y + (y+2)/9y - (2/6)y.  For example, without parentheses, your 8-y/3y might be interpreted differently, as 8   -   y/(3y), or 8 - 1/3.

Looking at (8-y)/3y + (y+2)/9y - (2/6)y again, we see three different denominators:  3y, 9y and 6 y.  The LCD here is 9y.  Multiplying all three terms of  (8-y)/3y + (y+2)/9y - (2/6)y by the LCD, we get:

3(8-y) + (y+2) + 3y.  We must now divide this by the LCD:

3(8-y) + (y+2) + 3y

--------------------------

            9y

Next we need to perform the indicated multiplication:

24 - 3y + y + 2 + 3y

----------------------------

            9y

and then to combine like terms:

24 + 2 - 3y + y + 3y,           26 + y

----------------------------   or    -----------

              9y                             9y

7 0
3 years ago
Read 2 more answers
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