All categories

2 years ago

Line AC is perpendicular to the

Mathematics

1 answer:

IRINA_888 [86]2 years ago

7 0

If the length of OA is 1.80 units. Then the length of segment AB will be 0.80 units.

<h3>What is a Pythagoras theorem?</h3>

The Pythagoras theorem states that the sum of two squares equals the squared of the longest side.

The Pythagoras theorem formula is given as

H² = P² + B²

Line AC is perpendicular to the circle centered at O with a radius of 1 unit. The length of AC is 1.5 units.

The figure is shown below.

Then the length of segment AB will be

AB = OA - OB

AB = OA - 1

Then the OA will be

OA² = OC² + AC²

OA² = 1² + 1.5²

OA² = 1 + 2.25

OA² = 3.25

OA = 1.80 units

Then we have

AB = 1.80 - 1

AB = 0.80 units

More about the Pythagoras theorem link is given below.

brainly.com/question/343682

#SPJ1

You might be interested in

Jarod read 36 pages out of his 180 page book.Which fraction represents the ratio of pages that Jared read to the entire book?

mojhsa [17]

$\frac{144}{180}$

4 0

3 years ago

Three times the difference of 5 and a number gives 30. Find the number.

Temka [501]

Answer:

Step-by-step explanation:

we need to write the equation. I came up with....

3(5 - x) = 30

so take the 3 away from the 30. I think your not supose to do the 3 because it out of the ( ). the opppisite of multiplication is division. so...

3 divided by 30 =10

rewrite

(5 - x) = 10

take the 5 away. the oppisite of subbtraction is addition.

5 + 10 = 15

check your; plug in x

3(5 - 15) = 30 This equation looks true!

Hope this helped! Please mark as brainliest! Thanks

5 0

4 years ago

The velocity v of blood that flows in a blood vessel with radius r and length ℓ at a distance r from the central axis is v(r) =

pogonyaev

$v(r)=4P\eta\ell(R^2-r^2)$

(assuming $R$ is the radius of the vessel, and that $0\le r\le R$ )

The average velocity of the blood is given by

$\displaystyle\frac1{R-0}\int_{r=0}^{r=R}v(r)\,\mathrm dr$
$=\displaystyle\frac{4P\eta\ell}R\int_{r=0}^{r=R}(R^2-r^2)\,\mathrm dr$
$=\dfrac{4P\eta\ell}R\left(\dfrac23R^3\right)$
$=\dfrac{8P\eta\ell}3R^2$