Line AC is perpendicular to the
1 answer:
If the length of OA is 1.80 units. Then the length of segment AB will be 0.80 units.
<h3>What is a Pythagoras theorem?</h3>The Pythagoras theorem states that the sum of two squares equals the squared of the longest side.
The Pythagoras theorem formula is given as
H² = P² + B²
Line AC is perpendicular to the circle centered at O with a radius of 1 unit. The length of AC is 1.5 units.
The figure is shown below.
Then the length of segment AB will be
AB = OA - OB
AB = OA - 1
Then the OA will be
OA² = OC² + AC²
OA² = 1² + 1.5²
OA² = 1 + 2.25
OA² = 3.25
OA = 1.80 units
Then we have
AB = 1.80 - 1
AB = 0.80 units
More about the Pythagoras theorem link is given below.
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The problem can be represented by the the exponential growth formula which is :
Where: t ⇒ time , A ⇒ initial amount , r ⇒ rate of increase
P(t) ⇒ predicted amount at the end of t.
For the given problem:
initial amount = A = $278,640
<span>predicted increase in value per year = 4% =0.04
</span>
<span>∴ r = 1 + 0.04 = 1.04
</span>
<span>for t = 18 years
</span>
∴
<span />
Rounding to the nearest dollar ⇒ ∴ P(t) = <span>564,474
</span>
So, the predicted value of David's home in 18 years = $564,474
So, The correct option is <span>$564,474</span>
Where: t ⇒ time , A ⇒ initial amount , r ⇒ rate of increase
P(t) ⇒ predicted amount at the end of t.
For the given problem:
initial amount = A = $278,640
<span>predicted increase in value per year = 4% =0.04
</span>
<span>∴ r = 1 + 0.04 = 1.04
</span>
<span>for t = 18 years
</span>
∴
Rounding to the nearest dollar ⇒ ∴ P(t) = <span>564,474
</span>
So, the predicted value of David's home in 18 years = $564,474
So, The correct option is <span>$564,474</span>
I could do that because both numbers are divisible by 7, and then they are divisible by 2. You could also have divided them by 14, but I think it's easier to do and explain this way.
Answer:
Step-by-step explanation:
Hello!
The contingency table is attached.
The total of pedestrians is 909, not 939, there are 30 accidents less in the given data.
I've calculated the asked probabilities using a total of 909.
1. The probability that the pedestrian was intoxicated or the driver was intoxicated.
Two events are mutually exclusive when the occurrence of one prevents the occurrence of the other in one single performance of the experiment. (i.e there is no intersection between the events P(A∩B)=0)
When two events are mutually exclusive, the probability of the union of both elements is equal to the sum of their individual probabilities P(A∪B)= P(A) + P(B).
When the events aren't mutually exclusive, the probability of their union is equal to the summary of their probabilities minus the probability of the intersection between these two events P(A∪B)= P(A) + P(B) - P(A∩B)
Where:
∪ is the union of both events, in colloquial language represents "or"
∩ is the union of both events, or intersection of the events, in colloquial language represents "and"
In this case P(P₁ ∪ D₁) = P(P₁) + P(D₁) - P(P₁ ∩ D₁) = = 0.393
P₁ and D₁ are not mutually exclusive
2. The probability of the pedestrian was intoxicated or the driver was not intoxicated.
These two events aren't mutually exclusive.
P(P₁ ∪ D₂)= P(P₁) + P(D₂) - P(P₁ ∩ D₂)= = 0.944
I hope it helps!
