All categories

3 years ago

In an orchestra, there are 42 woodwind players to 56 brass is ratio of woodwinds to brass written as a fraction in simplest form

1 answer:

8 0

$\frac{42}{56} = \frac{6}{8} = \frac{3}{4}$

I could do that because both numbers are divisible by 7, and then they are divisible by 2. You could also have divided them by 14, but I think it's easier to do and explain this way.

You might be interested in

Write 9.74 ×104 in standard notation

IRISSAK [1]

The answer is <span>012.96. Hope this helps!

</span>

4 0

3 years ago

Plsss help and please dont be scammer

gladu [14]

Answer:

38 students

Step-by-step explanation:

because 19% of 205 is 38.95, but not fully 39 students, so about 38 students

6 0

3 years ago

The density of a fish tank is 0.4fish over feet cubed. There are 12 fish in the tank. What is the volume of the tank?

ololo11 [35]

Answer: $30\ ft.^3$

Step-by-step explanation:

Given: Density of tank = 0.4 fish over feet cubed.

We know that, $\text{Density}=\frac{\text{Mass}}{\text{Volume}}$

Therefore,

$\text{Volume of the tank}=\frac{\text{Mass}}{\text{Density}}\\\\\Rightarrow\ \text{Volume of the tank}=\frac{12}{0.4}\\\\\Rightarrow\ \text{Volume of the tank}=30\ ft.^3$

Hence, the volume of the tank = $30\ ft.^3$

4 0

3 years ago

Read 2 more answers

3+3+3<br> Please Help....

NeX [460]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

9. A blueprint of a house plan uses a scale in

nata0808 [166]

Answer:

The length on the blueprint for an actual length of 65 feet is $16\frac{1}{4}\ inches$

Step-by-step explanation:

Given:

Scale of the blueprint is $\frac{1}{4}\ in=1\ foot$

Length of one side of the house is 65 feet.

Now, as per given data;

1 foot in actual = $\frac{1}{4}\ in$ on the blueprint.

Therefore, using unitary method, we can find find the length on the blueprint for an actual length of 65 feet by multiplying 65 and $\frac{1}{4}$ . Therefore,

Length on the blueprint for 65 feet is given as:

$=\frac{1}{4}\times 65\\\\=\frac{65}{4}\\\\=16\frac{1}{4}\ inches$

Therefore, the length on the blueprint for an actual length of 65 feet is $16\frac{1}{4}\ inches$

5 0

3 years ago