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Stella [2.4K]
3 years ago
7

I am very much lost if anybody understand this can u help me Please

Mathematics
1 answer:
stepan [7]3 years ago
3 0

Answer:

y= -2/7x-7

Step-by-step explanation:

slope intercept form is just a fancy way of saying y=mx+b

x being your input, y your output, m your slope, and b your y intercept

you can use the slope to determine your equation will look something like: y=-2/7x+b. To find your y-intercept all you do is determine how much the point will increase or decrease so it is equal to (0, y). In this case it will increase by 14 on the x's (so x is equal to 0) and 14*-2/7. When you have determined your y-int and slope you can then plug them into the equation instead of the variables.

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Jay simplified the expression -3 × (3 + 12 ÷ 3) - 4. For his first step, he added 3 + 12 to get 15. What was Jay’s error?
ale4655 [162]

Answer:

He should have divided 12 ÷ 3 first.

Step-by-step explanation:

Following PEMDAS/BODMAS, the first step is solving equations in parentheses. Since the parentheses contain a multi-step equation, Jay needs to follow PEMDAS for inside the parentheses as well. Instead of adding 3+12 first, he should have done division first (12  ÷ 3).

How the problem should be solved:

-3 × (3 + 12 ÷ 3) - 4

-3 × (3 + 4) -4

-3 × 7 - 4

-21 - 4

-25

3 0
3 years ago
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Express the quantity "1/3 revolutions per minute" in radians per second. Write your
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Answer:

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C. n/90 rad/sec.

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3 years ago
Yo yo Help a girl out LOL due today please help just need the answer <3
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Step-by-step explanation:

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3 years ago
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What is the general form of the quadratic with vertex at (2, 3) and passing through the point (5, 12)?
ki77a [65]

The general form of the quadratic with vertex at (2, 3) and passing through the point (5, 12) is x²-4x+7.

<h3>What is the vertex form of a quadratic equation?</h3>

Vertex form of the quadratic equation is used to find the coordinate of vertex points at which it crosses its symmetry.

The standard equation of the vertex form of quadratic is given as,

y=a(x-h)^2+k

Here, (h, k) is the vertex point.

The vertex of quadratic at (2, 3) and passing through the point (5, 12). Put the value of vertex point in the above equation,

y=a(x-2)^2+3

As the quadratic passes through the point (5, 12). Thus, put the value of this point,

12=a(5-2)^2+3\\12-3=a(3)^2\\9=a\times9\\a=\dfrac{9}{9}\\a=1

Put the value of <em>a</em> in the above expression,

y=1(x-2)^2+3\\y=(x-2)^2+3\\y=x^2-4x+4+3\\y=x^2-4x+7

Thus, the general form of the quadratic with vertex at (2, 3) and passing through the point (5, 12) is x²-4x+7.

Learn more about the vertex form here;

brainly.com/question/17987697

#SPJ1

4 0
3 years ago
What is the location of the second endpoint if the first endpoint is at (5,2) and
RUDIKE [14]
The second midpoint is (-15,8)
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3 years ago
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