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djverab [1.8K]
2 years ago
6

Help will give brainliest

Mathematics
1 answer:
mina [271]2 years ago
5 0

Answer:

0.7°

Step-by-step explanation:

From the figure:

CF = 4000.2 miles, CE = 4000.01 miles

so FT = √CF² - CT², TE = √CE² - CT²

so FT = 40 miles, TE = 8.94 miles

so ½ × 4000.2 × 4000.01

xsin angle FCE = ½ × 4000 × 140 + 8.94

so sin angle FCE = 0.0122

so angle FCE = 0.7°

so m SB = 0.7°

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Ben was walking in Manhattan at a constant speed. He went along 5th avenue from 4th to 98th street. At 3:00 he was on 15th stree
muminat

Answer: The starting time is 2:27 and finishing time is 7:09.    


Step-by-step explanation: It is given that Ben started from 4th street and he finished at 98th street.

Also, at 3:00, he was on 15th street and at 4:30, he was on 45th street.

That is, time taken to cover (45-15), i.e., 30 streets is 90 minutes,                           so the time taken to cover 1 street is 3 minutes.

Therefore, Ben covers distance from one street to second in 3 minutes. Since he started from 4th street, and there are 11 streets to cover between 4 and 15, so Ben's starting time was (3:00 - 3×11 min) = 2:27.

And his finishing time was (4:30 + 3×53 min) = 7:09.

Again, the equation that tells us on what street 'N' he was after time 'T' of his starting can be written as

N=4+\dfrac{T}{3.}

Thus, the starting and finishing time was 2:27 and 7:09 respectively.



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