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3 years ago

What is the rectangular form of 12(cos(Pi) + isin(Pi))? 12 -12 12 + i –12 + i

Mathematics

2 answers:

aliya0001 [1]3 years ago

8 0

Answer:

B, -12

Step-by-step explanation:

edge2020

dezoksy [38]3 years ago

5 0

Answer:

see answer below to make it easier.

Step-by-step explanation:

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Express the integral as an iterated integral in six different ways, where E is the solid bounded by y=4-x^2-4z^2 and y=0

zmey [24]

Assuming you need the integral expressing the volume of $E$ , the easiest setup is to integrate with respect to $y$ first.

This is done with either

$\displaystyle\iiint_E\mathrm dV=\int_{-2}^2\int_{-2}^2\int_0^{4-x^2-z^2}\mathrm dy\,\mathrm dx\,\mathrm dz$
$\displaystyle\iiint_E\mathrm dV=\int_{-2}^2\int_{-2}^2\int_0^{4-x^2-z^2}\mathrm dy\,\mathrm dz\,\mathrm dx$

Thanks to symmetry, integrating with respect to either $x$ or $z$ first will be nearly identical.

First, with respect to $x$ :

$\displaystyle\iiint_E\mathrm dV=\int_{-2}^2\int_0^4\int_{-\sqrt{4-y-z^2}}^{\sqrt{4-y-z^2}}\mathrm dx\,\mathrm dy\,\mathrm dz$
$\displaystyle\iiint_E\mathrm dV=\int_0^4\int_{-2}^2\int_{-\sqrt{4-y-z^2}}^{\sqrt{4-y-z^2}}\mathrm dx\,\mathrm dz\,\mathrm dy$

Next, with respec to $z$ :

$\displaystyle\iiint_E\mathrm dV=\int_{-2}^2\int_0^4\int_{-\sqrt{4-y-z^2}}^{\sqrt{4-y-x^2}}\mathrm dz\,\mathrm dy\,\mathrm dx$
$\displaystyle\iiint_E\mathrm dV=\int_0^4\int_{-2}^2\int_{-\sqrt{4-y-z^2}}^{\sqrt{4-y-x^2}}\mathrm dz\,\mathrm dx\,\mathrm dy$

5 0

3 years ago

Find the other endpoint of the line segment with the given endpoint and midpoint.

BARSIC [14]

Answer:

Step-by-step explanation:

16, -11

6 0

2 years ago

What is 1/5 as a hundredth?

crimeas [40]

Answer:

0.2

Step-by-step explanation:

5 0

3 years ago

The length of a rectangle in centimeters is two more than thrice its width. a) Write an expression, in the simplest form, for th

Karo-lina-s [1.5K]

Answer:

Perimeter of the rectangle = 8 x +4

Length of the rectangle = 12 units.

Step-by-step explanation:

Let the width of the rectangle as 'x' units.

So, length of the rectangle is 2 more than 3 x.

We can set up expression for length as 3 x+2.

Now, perimeter is sum of all side lengths of the rectangle.

So, perimeter = x+x+3 x+2 +3 x+2

Combine like terms,

Perimeter = 8 x+4

Now, it is given perimeter is 36cm

So,

8 x+4=36

Subtract both sides 4

8 x=32

Divide both sides by 8

x=4

So, width of the rectangle =4

Length =3(4) +2=14

3 0

3 years ago

A central angle θ in a circle of radius 4 m is subtended by an arc of length 5 m. find the measure of θ in degrees. (round your

koban [17]

Answer:

$\theta=71.6\°$

Step-by-step explanation:

step 1

Find the circumference of the circle

The circumference is equal to

$C=2\pi r$

we have

$r=4\ m$

substitute the values

$C=2\pi (4)=8 \pi\ m$

step 2

Remember that

360 degrees subtends the arc of length $8 \pi\ m$ (circumference)

by proportion

Find the measure of θ by an arc of length 5 m

assume $\pi=3.1416$

$\frac{360}{8\pi}=\frac{\theta}{5}\\ \\ \theta=360*5/8\pi \\ \\ \theta=71.6\°$

5 0

3 years ago