Mike and Lilly are working together on a science project. They agreed to
1 answer:
The <em>approximate distance</em> Mike and Lilly will have to travel between <em>halfway point and Library</em> is 7.8 miles.
<u>From the graph</u> :
- Mike's coordinate = (-4, 2)
- Lilly's coordinate = (2, - 2)
- Library coordinate = (4, 6)
<u>Meeting </u><u>point</u><u> </u><u>=</u><u> </u><u>Halfway</u><u> </u><u>point</u><u> </u><u>:</u>
(x1 + x2) /2 ; (y1 + y2) / 2
X - coordinate = (-4 + 2) / 2 = - 2/ 2 = - 1
Y - coordinate = (2 + (-2)) /2 = 0/2 = 0
Hence, meeting point = (-1, 0)
<u>The distance between meeting point and library</u> :
Distance = √[(x2 - x1)² + (y2 - y1)²]
Distance = √[(4 - (-1))² + (6 - 0)²]
Distance = √(25 + 36)
Distance = √61 = 7.8 miles
Therefore, the distance between halfway point and library ls approximately 7.8 miles
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Answer:
So the correct option is C ) 58 units.
Also If we require Distance then l(AC) = √58 = 7.615 units
Step-by-step explanation:
Let the Points be
point A( x₁ , y₁) ≡ ( -2 , 1)
point C( x₂ , y₂) ≡ (5 , -2)
To Find:
d(AC) = ?
Solution:
By Applying the Pythagorean Theorem to find the distance between points A and C we get
Substituting A( x₁ , y₁) ≡ ( -2 , 1) and C( x₂ , y₂) ≡ (5 , -2) we get
So the correct option is C ) 58 units.
If we require Distance then l(AC) = √58 = 7.615 units