Describe a real-life situation where you would have a remainder

2 answers:

swat323 years ago

8 0

Say you have eight people and nine apples and you want everyone to have the same amount of apples (which would be one), so you split them evenly and you have one apple left.

gavmur [86]3 years ago

6 0

Say you are at a party and there are 37 people and everyone gets the same amount as possible which is 9 per person so you will have 1 left over
HOPE THIS HELPS!!!! ;-)

You might be interested in

1.06g - 3 = 0.71 I need this answer

Arte-miy333 [17]

<span>Simplifying 1.06g + -3 = 0.71 Reorder the terms: -3 + 1.06g = 0.71 Solving -3 + 1.06g = 0.71 Solving for variable 'g'. Move all terms containing g to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + 1.06g = 0.71 + 3 Combine like terms: -3 + 3 = 0 0 + 1.06g = 0.71 + 3 1.06g = 0.71 + 3 Combine like terms: 0.71 + 3 = 3.71 1.06g = 3.71 Divide each side by '1.06'. g = 3.5 Simplifying g = 3.5</span>

7 0

3 years ago

Read 2 more answers

What is the area of a rectangle that is 12 meters by 8 meters

olchik [2.2K]

The area of a rectangle that is 12 meters by 8 meters is 96 square meters

5 0

4 years ago

Read 2 more answers

2(x - 6) Use Distribution

Galina-37 [17]

To distribute you first need to multiply 2 by x which equals 2x. Then you need to multilply 2 by -6 and that equals -12. Your final answer would be 2x-12

8 0

3 years ago

Read 2 more answers

Using the method of mathematical induction to prove that equalities are true for values of n indicated:

Dima020 [189]

$2^2+4^2+6^2+...(2n)^2=\frac{2n(n+1)(2n+1)}{3};\ n\geq1\\\\chek\ for\ n=1:\\L=2^2=4;\ R=\frac{2\cdot1(1+1)(2\cdot1+1)}{3}=\frac{2\cdot2\cdot3}{3}=4\\L=R\\-----------------------\\
assumption\ for\ n=k\\2^2+4^2+6^2+...+(2k)^2=\frac{2k(k+1)(2k+1)}{3}\\-----------------------\\thesis\ for\ n=k+1\\2^2+4^2+6^2+...+(2k)^2+[2(k+1)]^2=\frac{2(k+1)(k+1+1)[2(k+1)+1]}{3}\\-----------------------$
$proff:\\L=2^2+4^2+6^2+...+(2k)^2+(2k+2)^2=\frac{2k(k+1)(2k+1)}{3}+(2k+2)^2\\\\=\frac{(2k^2+2k)(2k+1)}{3}+\frac{3(2k+2)^2}{3}=\frac{4k^3+2k^2+4k^2+2k+3(4k^2+8k+4)}{3}\\\\=\frac{4k^3+6k^2+2k+12k^2+24k+12}{3}=\boxed{\frac{4k^3+18k^2+26k+12}{3}}\\\\R=\frac{2(k+1)(k+1+1)[2(k+1)+1]}{3}=\frac{(2k+2)(k+2)(2k+2+1)}{3}\\\\=\frac{(2k^2+4k+2k+4)(2k+3)}{3}=\frac{(2k^2+6k+4)(2k+3)}{3}=\frac{4k^3+6k^2+12k^2+18k+8k+12}{3}\\\\=\boxed{\frac{4k^3+18k^2+26k+12}{3}}\\\\L=R$

4 0

3 years ago

In the figure , a || b and m 1= 34 degrees <br> What is m 2 <br> _____ degrees

hram777 [196]

$m\angle 2=180-m\angle 1\\
m\angle 2=180-34\\
m\angle 2=146^{\circ}$

6 0

3 years ago