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2 answers:
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Answer:
The real zeros of f(x) are x = 0.3 and x = -3.3.
Step-by-step explanation:
Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
.
This polynomial has roots such that
, given by the following formulas:
In this problem, we have that:
So
The real zeros of f(x) are x = 0.3 and x = -3.3.
Answer:
f(-3) = 9
Step-by-step explanation:
Lets define f(a) first where a is any integer,
f(a) is found out by putting the integer in the function in place of the variable
So for the given question
In order to find f(-3) we will put -3 in place of x
So putting -3,
So, the value of function at -3 is 9 ..