we know that
Perimeter of a triangle is equal to
P=a+b+c
where
a,b and c are the length sides of the triangle
<u>Find the perimeter of the triangles</u>
<u>Triangle N 1</u>
P=(x-2)+(x)+(3x+1)-------> P=5x-1
<u>Triangle N 2</u>
P=(2x-5)+(x+4)+(6x-7)------> P=9x-8
equate the perimeters
5x-1=9x-8--------> 9x-5x=-1+8-------> 4x=7
x=7/4------> x=1.75
therefore
the answer is
x=1.75
5≥|4-2x|
5≥4-2x≥-5
-1≤2x≤9
-0.5≤x≤4.5
x∈[-0.5;4.5]
Answer:
11
Step-by-step explanation:
Step 1:
3/7r+5/8s
Step 2:
So u multiply 3/7 by 14
3/7 x 14= 42/7= 6
Step 2.5:
Now u multiply 5/8 by 8
5/8 x 8= 40/8= 5
Step 3:
<u><em>6+5=11</em></u>
Answer:
Step-by-step explanation:
AB/AC =1/2
(3x-4)/(2x+12)=1/2
2(3x-4) = 1(2x+12)
6x-8=2x+12
4x=20
X=5
AC/BC =3x-4/7x-2=22/33=2/3
AB/AC=3x-4/7x-2=22/33=2/3
AB/AC=3x-4/2x+12
6x-8=2x+12
You would get 4/5 still trying to work out the last mark
